28 ( x2, x3 and x4)
The GCF is x4
x5-1 = (x - 1)(x4 + x3 + x2 + 1)
x^4-x^3+x
The answer to this question is x4 easy right?!
28 ( x2, x3 and x4)
The GCF is x4
14
18xy is the GCF of 72x2y and 18xy
x5-1 = (x - 1)(x4 + x3 + x2 + 1)
(x - 1)(x4 + x3 + x2 + x + 1)
A power can be factored in many different ways; for example: x5 = x times x4 = x2 times x3. When such a power appears as a term in combination with other expressions, you should look out for common factoring patterns. Here are two examples: x2 + x5 Here, you can use the pattern "common factor". In this case, both parts have the common factor x2, so you can factor it out. x4 - 1 Here, you can use the pattern "difference of squares". Note that x4 is the square of x2, and 1 is the square of 1.
If there is a remainder then it's not a factor otherwise yes
The answer to x4+x3-14x2+4x+6 divided by x-3 is x3+4x2-2x-2
x4 - 1.We can not "solve" this as we have not been told the value of x. However, we can simplify this expression:We have an x and a minus x here which will cancel out. Likewise the x2 and x3 will cancel out with the -x2 and -x3 respectively. This therefore leaves us with just x4 - 1.
0.3333
X3xX4=X3+4=X7 this is the correct answer.