HCF(4a, 10a) = 2a.
2a
It appears to be 2a
b = 0.2 x 10a = 2aa/(2b) = a/(4a) = 1/4= 25%
To have a HCF, you need at least 2 numbers. There is no HCF in just 1 number.
The HCF is 5.
10a − 3 − 4a
10a + 3a - 4a = 9a
2a
6a-10a=16 -4a=16 a=-4
It appears to be 2a
to solve this expression: 10a-4(a+2) -> 10a-4(a)-4(2) -> 10a-4a-8 -> 6a-8
10a - 10 b
b = 0.2 x 10a = 2aa/(2b) = a/(4a) = 1/4= 25%
10a-37=6a+51 -6a -6a subtract 6a from both sides and the 6a's cancel 4a-37=51 +37 +37 4a=88 /4 /4 a=22
8a + 5g
Evaluate -4(a+b) - 10a/b when a=8 and b=5
2A/3 = 8 + 4A multiply by 3 both sides 2A = 24 + 12A subtract 2A to both sides 0 = 24 + 10A subtract 24 to both sides -24 = 10A divide by 10 both sides -24/10 = A -2.4 = A