Do the numbers first. The LCM of 6 and 8 is 24. Choose the highest of the powers. The LCM is 24a^3
280a4b2
12b2c3
72y^3
To find the Least Common Multiple (LCM) of 7, 3, and 21, we first need to identify the prime factors of each number. The prime factors of 7 are 7, of 3 are 3, and of 21 are 3 and 7. Then, we take the highest power of each prime factor that appears in any of the numbers. In this case, the LCM of 7, 3, and 21 is 21, as it includes the highest power of both 7 and 3.
Well, honey, the LCM of 6a and 8a is 24a. You see, you just gotta find the smallest number that both 6 and 8 can divide into evenly, and then slap on that 'a' like it's nobody's business. So, there you have it, 24a is the name of the game.
6a-3=8a+11 -3-11=8a-6a -14=2a a=-7
Do the numbers first. The LCM of 6 and 8 is 24. Choose the highest of the powers. The LCM is 24a^3
280a4b2
-8a + 6a + 7 = 1 -2a = 1 - 7 -2a = -6 a = 6/2 a = 3 Check: -8(3) + 6(3) + 7 = 1 -24 + 18 + 7 = 1 1 = 1
Well, honey, if you've got 5 apples and you take away 3 apples, you're left with 2 apples. Then if you subtract another 8 apples, you're in the negative with -6 apples. So, the answer is -6a. Hope that clears things up for ya!
8a - 15 = -3 8a = 15 - 3 8a = 12 a = 12/8 = 6/4 = 3/2
The variable is a. You can solve for it, like this: 8a - 9 = 7a - 6 8a = 7a + 3 8a - 7a = 3 a = 3
It is not clear whether the question is 3a + 4a + 5a + 6a^3 which would be 12a + 6a^3 or 3a + 4a + 5a + (6a)^3 = 12a + 216a^3 or (3a + 4a + 5a + 6a)^3 = 5832*a^3 But none of these really require summation notation!
11200
It depends on your value of a. However, if a is just a constant, you can simplify as such: 3-8a-1 = 2-8a
Since the question is 3(2a), then just write it out. 3(2a) is 2a+2a+2a or 6a.