Do the numbers first. The LCM of 6 and 8 is 24. Choose the highest of the powers. The LCM is 24a^3
280a4b2
12b2c3
72y^3
LCM is 96, which is the multiple of the highest power of prime factors in the given numbers (25 x 3).
6a-3=8a+11 -3-11=8a-6a -14=2a a=-7
Do the numbers first. The LCM of 6 and 8 is 24. Choose the highest of the powers. The LCM is 24a^3
280a4b2
-8a + 6a + 7 = 1 -2a = 1 - 7 -2a = -6 a = 6/2 a = 3 Check: -8(3) + 6(3) + 7 = 1 -24 + 18 + 7 = 1 1 = 1
8a - 15 = -3 8a = 15 - 3 8a = 12 a = 12/8 = 6/4 = 3/2
The variable is a. You can solve for it, like this: 8a - 9 = 7a - 6 8a = 7a + 3 8a - 7a = 3 a = 3
The LCM is 6b2c3
It is not clear whether the question is 3a + 4a + 5a + 6a^3 which would be 12a + 6a^3 or 3a + 4a + 5a + (6a)^3 = 12a + 216a^3 or (3a + 4a + 5a + 6a)^3 = 5832*a^3 But none of these really require summation notation!
11200
It depends on your value of a. However, if a is just a constant, you can simplify as such: 3-8a-1 = 2-8a
5a times 3a minus 8a = (5*3)*a2 - 8a = 15a2 - 8a
LCM[(13b3)3, 7b2] = LCM[2197b9, 7b2] = 2197*7*b9 = 15379*b9