Do the numbers first. The LCM of 6 and 8 is 24. Choose the highest of the powers. The LCM is 24a^3
280a4b2
12b2c3
72y^3
To find the Least Common Multiple (LCM) of 7, 3, and 21, we first need to identify the prime factors of each number. The prime factors of 7 are 7, of 3 are 3, and of 21 are 3 and 7. Then, we take the highest power of each prime factor that appears in any of the numbers. In this case, the LCM of 7, 3, and 21 is 21, as it includes the highest power of both 7 and 3.
The least common multiple (LCM) of 6a and 8a is the smallest number that is divisible by both 6a and 8a. To find the LCM, we need to first find the prime factors of each number. The prime factors of 6a are 2 x 3 x a, and the prime factors of 8a are 2 x 2 x 2 x a. The LCM is the product of all the unique prime factors with the highest power, so the LCM of 6a and 8a is 2 x 2 x 2 x 3 x a, which simplifies to 24a.
6a-3=8a+11 -3-11=8a-6a -14=2a a=-7
Do the numbers first. The LCM of 6 and 8 is 24. Choose the highest of the powers. The LCM is 24a^3
280a4b2
-8a + 6a + 7 = 1 -2a = 1 - 7 -2a = -6 a = 6/2 a = 3 Check: -8(3) + 6(3) + 7 = 1 -24 + 18 + 7 = 1 1 = 1
8a - 15 = -3 8a = 15 - 3 8a = 12 a = 12/8 = 6/4 = 3/2
The variable is a. You can solve for it, like this: 8a - 9 = 7a - 6 8a = 7a + 3 8a - 7a = 3 a = 3
It is not clear whether the question is 3a + 4a + 5a + 6a^3 which would be 12a + 6a^3 or 3a + 4a + 5a + (6a)^3 = 12a + 216a^3 or (3a + 4a + 5a + 6a)^3 = 5832*a^3 But none of these really require summation notation!
11200
It depends on your value of a. However, if a is just a constant, you can simplify as such: 3-8a-1 = 2-8a
Well, honey, if you've got 5 apples and you take away 3 apples, you're left with 2 apples. Then if you subtract another 8 apples, you're in the negative with -6 apples. So, the answer is -6a. Hope that clears things up for ya!
Since the question is 3(2a), then just write it out. 3(2a) is 2a+2a+2a or 6a.