(1 1 0 1)2 = (13)10
13 in decimal = 1101 in binary.
1110 0101 1101 1011 is E5DB
Lets do the binary addition of the numbers given that is , 1010 and 1101 that can be written as : 1010 +1101 ----------- (1 is carry)1 1 11. ------------
(4x1)+(2x0)+(1x1)=5. The first number is the place value. The second number is if there's a zero or a 1. Notice that the first number is half of the last first :) (last first) number. 1001=9. 1101=13. Who can do 10001101?
8
If 1101 is a decimal number, then its binary equivalent is 10001001101. If 1101 is a binary number, then its decimal equivalent is 13.
1101 is the binary equivalent of the decimal number 13
Jack Hill suggested "1101" instead; 1101 is the binary representation of the number 13
The binary number 1101 equals 13
13 in decimal = 1101 in binary.
13
13
1110 0101 1101 1011 is E5DB
13 = 1101
1101 = 8 + 4 + 1 = 13 (base 10).
Adding the numbers 1011 and 1101 in binary gives 11000 - equivalent to the decimal number 24.
11011+1101