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4x^2 - ox - 25 = 4x^2 - 25 which is a difference of two squares (DOTS)
= (2x)^2 - (5)^2
So, the factorisation is (2x + 5)*(2x - 5).
4x^2 - ox - 25 = 4x^2 - 25 which is a difference of two squares (DOTS)
= (2x)^2 - (5)^2
So, the factorisation is (2x + 5)*(2x - 5).
4x^2 - ox - 25 = 4x^2 - 25 which is a difference of two squares (DOTS)
= (2x)^2 - (5)^2
So, the factorisation is (2x + 5)*(2x - 5).
4x^2 - ox - 25 = 4x^2 - 25 which is a difference of two squares (DOTS)
= (2x)^2 - (5)^2
So, the factorisation is (2x + 5)*(2x - 5).
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