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4x^2 - ox - 25 = 4x^2 - 25 which is a difference of two squares (DOTS)

= (2x)^2 - (5)^2

So, the factorisation is (2x + 5)*(2x - 5).

4x^2 - ox - 25 = 4x^2 - 25 which is a difference of two squares (DOTS)

= (2x)^2 - (5)^2

So, the factorisation is (2x + 5)*(2x - 5).

4x^2 - ox - 25 = 4x^2 - 25 which is a difference of two squares (DOTS)

= (2x)^2 - (5)^2

So, the factorisation is (2x + 5)*(2x - 5).

4x^2 - ox - 25 = 4x^2 - 25 which is a difference of two squares (DOTS)

= (2x)^2 - (5)^2

So, the factorisation is (2x + 5)*(2x - 5).

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Wiki User

10y ago

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More answers

4x^2 - ox - 25 = 4x^2 - 25 which is a difference of two squares (DOTS)

= (2x)^2 - (5)^2

So, the factorisation is (2x + 5)*(2x - 5).

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Wiki User

10y ago
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Factor (−1)×17

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(2x + 5)*(2x - 5).

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Lucky

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2y ago
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Q: What is the correct factorization of 4x2-0x-25?
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