2 x 3 x 5 x d x d x d x d x d = 30d5
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yes, 5(c-d) this means 5 times c-d
18xxx-39xx-15xFactor out common factor (3x)3x(6xx-13x-5x)axx+bx+c3x(6xx-13x-5)a=6b=-13c=-5Multiply a and c:6*-5=-30Find multiples of ac that add up to b (d,e [ie de=ac, d+e=b]):-30=-1*2*3*5-30=-1*30, 1*-30-30=-2*15, 2*-15-30=-3*10, 3*-10-30=-5*6, 5*-6Rewrite axx+bx+c into axx+dx+ex+c:3x(6xx-13x-5)3x(6xx+x-30x-5)Factor sets of terms (ie axx+dx, and ex+c):3x(6xx+x-30x-5)3x(x(6x+1)-5(6x+1))Combine like terms:3x(x(6x+1)-5(6x+1))3x(x-5)(6x+1)
8 is a factor of 40
no it does not matter what two factors you select to complete a factor tree (i just learned that today in class :D)
It depends on the precise definition of d.