x - 3
(x - 9)(x + 6)
The GCF is x2.
-79
(x + 4)(x + 9)
9 - x2 will factor into (3 - x)(3 + x)
x2-9x = x(x-9)
Factor x4 - 81. Step 1: both numbers have square roots and have a minus sign between them so the first factor result is (x2+9)(x2-9). Step 2: (x2+9) does not factor, but (x2-9) factors to (x+3)(x-3). Step 3: Solution is (x2+9)(x+3)(x-3).
(x2 - 3)(x2 + 3)(x4 + 9)
x2-6x+9 = (x-3)(x-3) when factorised.
9 - x2 = 32 - x2 = (3 - x)(3 + x)
(x - 9)(x + 1)
x -9
x2 + 9 + 20 = x2 + 29, and can not be factored.I assume though that you mis-wrote your question, and what you in fact want to ask is how to factor x2 + 9x + 20.In that case, the answer is (x + 4)(x + 5).
To factor any term, divide by the LCF (largest common factor) of the term. For 5x2-45, the LCF is 5. 5x2-45 = 5(x2-9) It can, of course, be factored even further to become: 5(x2-9) = 45(x2/9 - 1) but when factoring, we usually don't need to go past 5(x2-9) (for example, you've figured out that x2 = 9, thus x = +/- 3.)
(x-9)(x+9)
First, it is important to regroup, so I am going to rearrange this equation: (x4 - 7x2 - 18 - 3x3 + 27x I can now factor the first three terms and the last two terms: (x4 - 7x2 - 18) becomes (x2 - 9)(x2 + 2) -3x3 + 27x becomes -3x(x2 - 9); so the new equation looks like: (x2 - 9)(x2 + 2) - 3x(x2 - 9) From here, factor out what is common, in this case- x2- 9. Therefore, you will have (x2 - 9)(x2 + 2 - 3x), which can be rearranged to (x2 -9)(x2 - 3x + 2). Further factoring reveals (x + 3)(x - 3)(x - 1)(x - 2) as the final answer.