32 x 29 = 261
the prime factors of 725 using exponents are 5^2 x 29
As a product of its prime factors in exponents: 22*3*7 = 84
Sure thing, darling. The prime factorization of 55 is 5 x 11. If we want to use exponents, we can write it as 5^1 x 11^1. So there you have it, sweetie, prime factor of 55 using exponents in a nutshell.
225 prime factors are 32 and 52
12 = 22 x 31
The prime factors of 20 using exponents is: 22x 5
the prime factors of 725 using exponents are 5^2 x 29
As a product of its prime factors in exponents: 22*3*7 = 84
The prime factors of 40 in exponential form are 23 x 5.
The prime factors of 26 are 2 and 13.
The prime factors of 200 are: 23 x 52
It is: 2*5*7 = 70 and no exponents are needed
Sure thing, darling. The prime factorization of 55 is 5 x 11. If we want to use exponents, we can write it as 5^1 x 11^1. So there you have it, sweetie, prime factor of 55 using exponents in a nutshell.
225 prime factors are 32 and 52
As a product of its prime factors using exponents: 2^3 times 3 times 5 = 120
22 x 32 = 36
To find the prime factorization of 333 using exponents, we first need to break it down into its prime factors. 333 can be factored as 3 x 3 x 37. Writing this in exponential form, we get 3^2 x 37. Therefore, the prime factorization of 333 using exponents is 3^2 x 37.