The GCF is 13xy.
The GCF is 3.
y = x2
The GCF is y.
The GCF of 27 x^2 y^3 and 46 x^2 y is xy^2. 27 and 46 are coprime.
To write this algebraically: 7(y^3)|y = 2 Substitute 2 for y: 7(2^3) 2^3 = 8, so substitute 8 for (2^3): 7*8 = 56
If y equals 3, 7 - 5y would be:7 - 5(3)Simplify.7 - 15 = -8.In conclusion, 7 - 5y = -8.
7 and the y intercept is 8/3
7/3 im pretty sure Another Answer:- If: 7x = 3y-8 Then: -3y = -7x-8 And so: y = 7/3x+8/3 Therefore: the slope is 7/3 and the y intercept is 8/3
Put in this form. Y = mX + c3X - 7Y = 8- 7Y = - 3X + 8Y = (3/7)X - 8/7===========Y intercept = - 8/7-----------------------
To find the GCF of 9x^2y and 39xy^3 first look at the GCF of 9 and 39 with is 3 Now the GCF of x^2 and x is x and the GCF of y^3 and y is y so the GCF of the 9x^2y and 39xy^3 is 3xy Use a similar idea to find the LCM. The LCM of x^2 and x is x^2 and the LCM of y^3 and y is y^3, lastly, the LCM of 9 and 39 is 117 so the LCM is 117x^2y^3
You have two equations with two unknowns, y and x To solve, y = -3x +7 y = 2x -8 since they are equal -3x + 7 = 2x-8 7= 5x -8 15 = 5x 3 = x substitute in either equation to get y y = -2
The value of y works out as -3 because both points must be equal distance from the center of the circle at (5, 2) and so the points are (2, -3) and (8, 7)
I'm going to answer it. y=-sqrt6x+3, y=-3rt8x+5 y=(-sqrt6x^2)+3, y=(-3rt8x^3)+5 y=-6x+3, y=-8x+5 Let's add them. 2y=-14x+8 Let's say y=0. 2(0)=-14x+8 0=-14x+8 Now we can solve for x. -14x+8=0 -14x+8-8=0-8 -14x=-8 -14x/-14=-8/-14 x=4/7 Time to see if this is right. 0=-sqrt6(4/7)+3 0=-3rt8(4/7)+5 Time to fix this. 0=(-sqrt6(4/7)^2)+3 0=(-3rt8(4/7)^3)+5 That leaves you with these two equations. 0=-6(4/7)+3 0=-8(4/7)+5 Let's combine these two. 0=-14(4/7)+8 0=-8+8 0=0 Therefore,x=4/7, and y=0.
The GCF is y6
The GCF is 13xy.
x=5 y=-3