The GCF is 5x3
8c cubed
3k
the GCF is 8x
Since 3y2 can evenly divide 24y3, 3y2 must be the greatest common factor, since the greatest common factor cannot be larger than the smaller of the two numbers. But, we can also look at a factorization of both numbers. We can tell that 3y2 = 3 x y2. We can tell that 24y3 = 3 x 8 x y3 = 3 x 23 x y2 x y. These numbers have in common 3 and y2, so 3y2 is the greatest common factor.
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8c cubed
3k
the GCF is 8x
The GCF is a2b
Since 3y2 can evenly divide 24y3, 3y2 must be the greatest common factor, since the greatest common factor cannot be larger than the smaller of the two numbers. But, we can also look at a factorization of both numbers. We can tell that 3y2 = 3 x y2. We can tell that 24y3 = 3 x 8 x y3 = 3 x 23 x y2 x y. These numbers have in common 3 and y2, so 3y2 is the greatest common factor.
The question cannot be answered because the powers of a and b, at the start of the expression are not specified.
All that is factorable here is the common factor t.t3 - 8tt(t2 - 8)======
5x^2(4x - 5)(5x + 11)
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No. Four cubed means four to the third power.
One is the only factor of 50 that is a cube.
The GCF is 3.