0
Assuming you mean 30y^3 and 20y^2,
We ought to factorise to check our answers.
The greatest number that divides into both 30 and 20 is 10.
The greatest y term that divides into both y^3 and y^2 is y^2
So,
10y^2 (3y + 2)
If we multiplied out brackets above, we would be left with 30y^3 + 20y^2
Since (3y +2) cannot be simplified any further,
Ans = 10y^2
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