3m
(3m + 2)(2m - 5)
No, 30dm = 3m.
The GCF of 9m and 3 is 3. You are left with 3m and 1. These cannot be further reduced by common factors.
The GCF of 12m, 15m and 30m is 3m.
3m
a is 3m b is 3n m and n are relatively prime - they do not have any common factors. a2 = 9m2 Since m had no factors in common with n, m2 also has no factors in common with n. We know that 3 is a common factor of a and b. The only new possible factor between a2 and b is the second 3 when a is squared. We do not know whether b had more than one factor of 3. So, the greatest common factor of a2 and b, when the greatest common factor of a and b is 3, is either 3 or 9.
m(3m + 2)
6(3m - 2n)(3m + 2n)
0
There is a formula for the "difference of squares." In this case, the answer is (3m + 13n)(3m - 13n)
3m, 305cm, 35dm, 31km
3m^2 - 9m = 0 factor out 3m 3m(m - 3) = 0 m = 0 -------- or m = 3 --------
1 and 3m is one possible pair.
(m + 5)(3m - 1)
8
3m(2m + 5)