There is no highest Prime number. Given any set of prime numbers, you can prove that there is at least one prime number that is not in that set. Here's how.
First, recall that every natural number is either a prime number, or is a composite number and thus the product of some series of prime numbers.
Now, suppose you have a set of n prime numbers, P1 .. Pn. Multiply them all together and add one. Call this number Q.
Q is either prime or composite.
If Q is prime, then it is obviously not one of P1 .. Pn, and thus is a new prime number not in that set.
If Q is composite, then there must be a list of primes that evenly divide into it. Because Q is one greater than the product of P1 .. Pn, dividing by any of those primes will have a remainder of 1. So there must be some new prime, call it R, that divides evenly into Q.
In either case, Q or R is a new prime.
Now suppose that you have some potential highest prime. Enumerate all of the primes lower than it, and follow the above procedure with that set of primes. You will end up with a new prime not in that list. Since you have listed all primes less than your purported highest prime, any new prime number must be greater than your highest prime.
Thus, there is no highest prime.
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99 is not a prime because it can be divisible by 3 and 33
To find the highest prime factor of 420, we first need to factorize 420 into its prime factors. 420 can be expressed as 2^2 * 3 * 5 * 7. The highest prime factor is 7. Prime factors are numbers that can only be divided by 1 and themselves without leaving a remainder, and the highest prime factor is the largest prime number that can divide the original number.
9973.
We can't answer this if you don't provide a range since new higher prime numbers get discovered every year or so. Since the lowest prime number is 2, the product will be whatever the highest prime number is doubled.
It is 997.It is 997.It is 997.It is 997.