Four bits are required to write '12' as a binary number.
(12)10 = ( 1 1 0 0 )2
Oh, dude, the least common multiple of 4 and 12 is like the smallest number that both 4 and 12 can divide evenly into. So, basically, it's the smallest number where these two numbers can hang out and party together without any leftovers. In this case, the least common multiple of 4 and 12 is 12, because 12 is the smallest number that both 4 and 12 can divide into without any remainders.
The least common multiple of 12, 20 and 24 is 120.
The least common multiple (LCM) of 5 and 12 is 60.
Oh, isn't that a happy little question! To find the least common multiple of 6 and 12, we can look at their multiples: 6, 12, 18, 24, 30, 36... and so on. The least common multiple is the smallest number that both 6 and 12 can divide into evenly, which in this case is 12. Just like painting, math can be a joyful journey of discovery!
You can't have an LCM of a single number. The LCM of 12, 15 and 25 is 300.
To determine the least number of bits required to distinguish among 12 different choices, you can use the formula (2^n \geq 12), where (n) is the number of bits. The smallest (n) that satisfies this is (n = 4), since (2^4 = 16), which is greater than 12. Therefore, at least 4 bits are required to uniquely identify 12 different options.
12/1
12 more than a number means: __+12 (a number plus 12). You can express this as an algebraic expression: n+12 or 12+n(n representing a number.)
2
12 bits = 1-1/2 bytes.
The least number that is divisible by the first 12 counting numbers (1 through 12) is known as the least common multiple (LCM) of those numbers. The LCM of 1 through 12 is 27720. This means that 27720 is the smallest number that can be evenly divided by each of the first 12 counting numbers.
12
8 is less than 12.
3.75
12 and 18 have 36 as their least common multiple(lcm)
120
100000000000