Yes. To be composite, the first number has at least 2 prime factors, the second number also has at least prime factors; the product of the two will have at least 4 prime factors, so it must be a composite number.
The number that has both the factors 4 and 6 is the least common multiple (LCM) of 4 and 6. To find the LCM, we need to identify the prime factors of each number. The prime factors of 4 are 2^2, and the prime factors of 6 are 2 * 3. To find the LCM, we take the highest power of each prime factor that appears in either number, which gives us 2^2 * 3 = 12. Therefore, the number that has both the factors 4 and 6 is 12.
The smallest prime factors are 2,3,5,7 thus the smallest number would be the product of these will be 210
Three is the prime number. Both 10 and 4 have factors other than themselves.
a prime number has no factors other than one and itself 4:1,2,4 10:1,2,5,10 3:1,3 3 is the prime number!!!! it's only factors are one and itself!!!!
abcabc=abc x 1001 1001 = 7 x 11 x 13 So such number as at least 4 prime factors: if abc is prime, then 4 factors only if abc is not prime then at least 4 factors
Yes. To be composite, the first number has at least 2 prime factors, the second number also has at least prime factors; the product of the two will have at least 4 prime factors, so it must be a composite number.
No, 4 has one prime factor.
Logically, the smallest number with 4 different prime factors would have to be the product of the smallest four prime numbers. So the smallest natural number with four different prime factors is 210 (2*3*5*7).
a negative prime number has 4 factors
295 is not a prime number because it has a factor of 5, while prime numbers only have factors of itself and 1. 295 can be divded by 5, giving it at least 4 factors, and thus disqualifies it from fitting the definiton of a prime number.
No, a prime number has exactly two factors: 1 and itself.
No, it is not possible. Every multiple of 21 is a composite number. 21 is a composite number and its factors are 1, 3, 7 and 21(4 factors). Any multiple of 21 must have all the factors of 21. So, every multiple of 21 has at least 4 factors. And a prime number has only two factors so, any multiple of 21 can't be prime.
The factors of 4 are 1, 2, and 4. The only prime factor of 4 is 2. The factors of 20 are 1, 2, 4, 5, 10, and 20. The prime factors of 20 are 2x2x5.
Three is prime, because the number 3 only has 2 factors 1 and itself and the number 4 has 3 factors 1,2, and 4 (you can tell if a number is prime when it has 2 factors and if a number has more than 2 it is composite)
Well, isn't that a happy little question! To find the least number that has 2, 3, and 4 as factors, we need to look for the smallest number that is divisible by all three. We can achieve this by finding the least common multiple of 2, 3, and 4, which is 12. So, the number you're looking for is 12. Happy calculating!
To find the least common denominator of 143 and 208, we need to first find the prime factors of each number. The prime factors of 143 are 11 and 13, while the prime factors of 208 are 2, 2, 2, 2, 13. The least common denominator is the product of all the prime factors with the highest power present in either number, which is 2^4 * 11 * 13 = 1144. Therefore, the least common denominator of 143 and 208 is 1144.