x = 484
64 = 4 cubed and 8 squared.
2744
1729 is the smallest number that can be expressed in two ways as the sum of two cubes.[12cube+9cube] * * * * * ... two positive cubes. 12 cube + 1 cube and 10 cube + 9 cube.
3
Sure, honey, let me break it down for you. No, a prime number cannot be a perfect cube because a prime number is only divisible by 1 and itself. And let me tell you, a perfect cube is the result of multiplying a number by itself three times, so a prime number ain't gonna fit that bill. So, in short, a prime number and a perfect cube are like oil and water - they just don't mix, darling.
2
10
The only solution is that a = 5 then 25a = 25 x 5 = 52 x 5 = 53.
45
5
To find the least positive integer ( k ) for which ( 15k ) is a cube, we start with the prime factorization of 15, which is ( 3^1 \times 5^1 ). For ( 15k ) to be a perfect cube, the exponents in its prime factorization must be multiples of 3. Thus, we need to make the exponents of both 3 and 5 in ( 15k ) equal to 3. Therefore, ( k ) must contribute ( 3^2 ) (to make the exponent of 3 equal to 3) and ( 5^2 ) (to make the exponent of 5 equal to 3). Thus, ( k = 3^2 \times 5^2 = 9 \times 25 = 225 ). Therefore, the least positive integer ( k ) is ( 225 ).
It is the additive inverse of itself, it is the square, cube, ... any positive power of itself.
A cube is any number multiplied by itself three times, eg 2 cubed = 2³ = 2×2×2 = 8; 1.5³ = 1.5×1.5×1.5 = 3.375 A perfect cube is an integer (whole number) that is the cube of an integer, eg 8 is a perfect cube as it is 2 cubed, but 9 is not a perfect cube as 9 = 2.08008382...³
No, 11025 is not a perfect cube. A perfect cube is an integer that can be expressed as the cube of another integer. The cube root of 11025 is approximately 22.2, which is not an integer, indicating that 11025 cannot be written as ( n^3 ) for any integer ( n ).
Here is a method: cube root of 400g = n, where n is an integer cube both sides: 400g = n3 then: g = n3/400 therefore: n3/400 must be an integer if this is so, then n3 must be divisible by 400 with no remainder, and n must be => cube root of 400 which is 7.368 bracket the answer by substitution: let n=8, n cubed = 512 no good let n=12, n cubed = 1728 no good let n=20, n cubed = 8000, 8000/400=20 OK No smaller value of n will be divisible by 400 without a remainder, so g=20 is the smallest positive integer that meets the requirement.
Finding the square root of a positive integer involves identifying a number that, when multiplied by itself, equals the original integer, resulting in one non-negative solution. In contrast, finding the cube root of a positive integer determines a number that, when multiplied by itself twice (i.e., raised to the power of three), equals the original integer, yielding one real solution. The key difference lies in the operations involved: square roots deal with pairs of factors, while cube roots involve triplets. Additionally, cube roots can yield real solutions for negative integers, unlike square roots.
an integer