You would get calcium chloride... 2HCl + Ca(OH)2 = CaCl2 + 2H2O
The mass of 3,400 mol Ca(OH)2 is 251,9 g.
m sub Ca(OH)2 = ( 10 g Ca ) [ ( 74.12 g Ca(OH)2 ) / ( 40.078 g Ca) ] m sub Ca(OH)2 = 18.5 g Ca(OH)2 <------------------
If you trhink to calcium hydroxide - Ca(OH)2 - this mass is 148,086 g.
The mass of 7,346 moles of Ca(OH)2 is 544,3 g.
240gm
Percent CompositionFirst you have to find all the atomic masses of the elements involved in the compound. Then you have to add them up to get the total molecular mass. Take the atomic mass of Ca and divide it by the total mass. Multiply it by 100 and you will get the percent of Ca in any compound of Ca(OH)2. Once you know the percent composition, you can take Ca's percent from the whole sample. Ca: 40.1O: 16.0×2 = 32.0H2: 1.0×2 = 2.0Ca(OH)2: 74.1 grams(40.1 ÷ 74.4) × 100 = 53.9 % of Ca in Ca(OH)253.9 % of 5.00 grams = 2.67 grams of Ca in Ca(OH)2
Calcium hydroxide (Ca(OH)2) has a molar mass of 74g/mol. To find the number of moles in 0.5000g of calcium hydroxide, you divide the 0.5000gCa(OH)2 by 74gCa(OH)2. The answer is 0.006757mol Ca(OH)2 to the nearest significant figure.
Molecular mass of calcium oxide = calcium (40,078) + oxygen (15,9994) = 56,0774 56,0774 CaO--------------40,078 Ca 100 g CaO-----------------x g Ca x = (40,078 x 100)/56,o774 = 71,469 % Ca
The chemical formula for calcium hydroxide is Ca(OH)2. Ca: 40.08 O: 16.00 H: 1.01 Molar mass= 74.10 g Ca(OH)2
There are two types of ions in this compound, calcium ions and hydroxyl ions. The number of ions present in a sample can be calculated if the mass of the sample is known.
Mercury (I) Hydroxide Hg OH2 (2 is subscript) Mercury(II) Hydroxide Hg (OH)2