There are 10 numbers. To find the median, you need to do 10/2 + 1
10/2 = 5
5+1 = 6
57 - 59 - 61 - 67 - 71 - 73 - 79 - 83 - 87 - 89
The odd numbers between 70 and 90 are 71, 73, 75, 77, 79, 81, 83, 85, 87, and 89. We know right away that 75 and 85 are composite, since they're divisible by 5. 81 is composite since it is the square of 9. 77 is obviously divisible by 11, so it, too, is composite. 87 is divisible by 3 since 8 + 7 = 15, which is divisible by 3. Therefore, and trust me, I double-checked the rest, 75, 77, 81, 85, and 87 are the composite, odd numbers between 70 and 90.
02, 03, 05, 07, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97100~01, 03, 07, 09, 13, 27, 31, 37, 39, 49, 51, 57, 63, 67, 73, 79, 81, 91, 93, 97, 99200~11, 23, 27, 29, 33, 39, 41, 51, 57, 63, 69, 71, 77, 81, 83, 93300~07, 11, 13, 17, 31, 37, 47, 49, 53, 59, 67, 73, 79, 83, 89, 97400~01, 09, 19, 21, 31, 33, 39, 43, 49, 57, 61, 63, 67, 79, 87, 91, 99500~03, 09, 21, 23, 41, 47, 57, 63, 69, 71, 77, 87, 93, 99600~01, 07, 13, 17, 19, 31, 41, 43, 47, 53, 59, 61, 73, 77, 83, 91700~01, 09, 19, 27, 33, 39, 43, 51, 57, 61, 69, 73, 87, 97800~09, 11, 21, 23, 27, 29, 39, 53, 57, 59, 63, 77, 81, 83, 87900~07, 11, 19, 29, 37, 41, 47, 53, 67, 71, 77, 83, 91, 97
71 73 79 83 89 97.
No. They are both divisible by 3.
That's an infinite list. 81, 83, 85, 87, 89, 91 and so on.
61 + 73 + 71 + 80 + 87 + 90 + 90 + 90 + 87 + 83 + 73 + 63 = 948 / 12 = 79 The average of the numbers is therefore 79.
The median is 87.
You add up the numbers, then divide by how many numbers you added. Here there are 4 numbers to add up: 81+83+87+85. Use a calculator or do longhand. Then divide the sum by 4 to get the average.
78
The standard deviation of the scores 100 92 94 95 81 82 87 89 71 71 73 61 62 68 51 55 is: 15.1921
86.90909090 recurring or 86 and one eleventh.
The integers are 81, 83, 85 and 87.
.81 .82 .83 .84 .85 .86 .87 .89
There are four consecutive odd integers: 81, 83, 85 and 87.
82.83
57 - 59 - 61 - 67 - 71 - 73 - 79 - 83 - 87 - 89