Given any number it is easy to find a polynomial rule of order 6 such that the first six numbers are the above six and the seventh is the given number. That is, I can find a rule so that anynumber can be the "next" in the sequence.
In this case, you can fit the following quartic:
Un = (n4 - 6n3 + 35n2 + 6n - 12)/12 for n = 1, 2, 3, ...
and accordingly, the next number is 174.
14
The sequence appears to be increasing at a variable rate. The pattern seems to be adding 1, then 3, then 5, then 10. Following this pattern, the next number in the sequence would be 20 + 15, which equals 35.
A number sequence is not a question. So there can be no "answer".
The next composite number after 20 is 21.
I would make it 1 The above sequence is the numerical order of some of the numbers on a dart board
next in the sequence: 10,20,30,20
The next number in the sequence will be 56.
20
The next number in the sequence 5, 10, 20, 40 is 80. Each number in the sequence is multiplied by 2 to get the next number. So, 40 multiplied by 2 equals 80.
10
25 is the next number that appears in that sequence.
500
10 is one possibility.
20
10
20
20