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- First of all, it's CuSO4*5H2O (notice the capital "O" in the first part of the formula). The compound is called copper(II) sulfate pentahydrate, and if we wish to find the percent by mass of water, we need to find the molar mass of the hydrate first.
Cu = 63.55 g/mol
S = 32.07 g/mol
O x 4 = 16.00 g/mol x 4 = 64.00 g/mol
H2O x 5 = 18.02 g/mol x 5 = 90.10 g/mol
Now add them all together and you get a molar mass of 249.72 g/mol
Of that 249.72 grams, 90.10 grams is water, so to find the percentage by mass that is water, simply divide 90.10 g by 249.72 g and multiply the result by 100%:
90.10 g / 249.72 g x 100% = 36.08% water
Wiki User
∙ 10y ago
Bhagvan Kumbhar
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How many grams of copper sulfate pentahydrate CuSO4 5H2O would you heat to produce 29.8 g of water?
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
The equation for the dehydration of CuSO4 5H2O heat?
their isn't one CuSO4 is an anhydrous salt which will absorb water so the way to find out how much is in it is to find out the difference in water befor and after addition and calculate it by finding the mols of water absorbed incomplarison with the number of mols of CuSO4 used. it is normally wrighten nH2O. CuSO4
How many grams of copper sulfate would you heat to produce 29.8g of water?
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
What is the formula for hydrated copper II sulfate?
Copper sulfatepentahydrate is a solid at 20 degrees Celsius has a density of 2.28g/cm3 (cubed)... and its' chemical symbol is CuSO4-5H2O
Is the percent by mass of copper in CuSO4 5H2O the same as in CuSO4?
No. The % of Cu by mass in CuSO4 will be greater than the % of Cu by mass in the pentahydrate (5H2O) because in the hydrate there is added mass (5 H2O = 90 g) but no added Cu.
What is a balanced equation for the decomposition of copper sulfate pentahydrate?
CuSO4•5H2O + heat ---> CuSO4 + 5H2O
What is the reaction CuSO4 5H2o plus heat?
CuSO4 * 5H2O ----> CuSO4 + 5H2O. This is true because CuSO4 * 5 H2O is a salt weakly bounded to water, that is why it is hydrous. When it decomposes, the weak bonds are broken making the products above. CuSO4*5H2O formula is [Cu(OH2)4]SO4*H2O CuSO4 + 5H2O --> [Cu(OH2)4]SO4*H2O
What is the Empiracal formula for cupric sulfate pentahydrate?
CuSO4•5H2O
What is the chemical formula of cupric bi sulfate?
CuSO4 5H2O
What is the balanced equation for copper sulphate pentahydrate?
CuSO4 * 5H2O
What is the balanced equation when copper ll sulfate pentahydrate is heated?
cuso4 - 5h2o= cuso4 + 5h20 + heat
