72%
85%
25%
10%
there is 43% of water in the red blood cells
I cannot answer it,i need help
their isn't one CuSO4 is an anhydrous salt which will absorb water so the way to find out how much is in it is to find out the difference in water befor and after addition and calculate it by finding the mols of water absorbed incomplarison with the number of mols of CuSO4 used. it is normally wrighten nH2O. CuSO4
CuSO4 • 5H2O → CuSO4 + 5H2O + heat
No, the percent by mass of copper in CuSO4 5H2O will be different than in CuSO4 because CuSO4 5H2O includes water molecules in addition to the copper sulfate compound itself. Therefore, the total mass of CuSO4 5H2O will be greater, resulting in a lower percent by mass of copper in CuSO4 5H2O compared to CuSO4.
Hydrated copper sulfate, CuSO4·5H2O, contains 36.10% water by mass.
The balanced chemical equation for the decomposition of copper sulfate pentahydrate (CuSO4·5H2O) to produce anhydrous copper sulfate (CuSO4) and water vapor (H2O) is: CuSO4·5H2O → CuSO4 + 5H2O.
To calculate this, we first determine the molar mass of water (H2O) and copper sulfate pentahydrate (CuSO4 5H2O). Then we can use stoichiometry to find the mass of copper sulfate pentahydrate needed to produce 29.8g of water through the reaction.
The balanced equation for the heating of copper(II) sulfate pentahydrate (CuSO4•5H2O) is: CuSO4•5H2O(s) -> CuSO4(s) + 5H2O(g). This reaction decomposes the pentahydrate compound into anhydrous copper(II) sulfate and water vapor.
CuSO4 · 5H2O has 5 water molecules attached to each CuSO4 molecule.
CuSO4 * 5H2O ----> CuSO4 + 5H2O. This is true because CuSO4 * 5 H2O is a salt weakly bounded to water, that is why it is hydrous. When it decomposes, the weak bonds are broken making the products above. CuSO4*5H2O formula is [Cu(OH2)4]SO4*H2O CuSO4 + 5H2O --> [Cu(OH2)4]SO4*H2O
The ratio of moles of CuSO4 to moles of water in CuSO4•5H2O is 1:5. This is because there is one mole of CuSO4 for every five moles of water in the compound.
Copper sulfatepentahydrate is a solid at 20 degrees Celsius has a density of 2.28g/cm3 (cubed)... and its' chemical symbol is CuSO4-5H2O
The structural formula of CuSO4·5H2O is Cu(H2O)4SO4, where the copper ion (Cu) is surrounded by four water molecules (H2O) and one sulfate ion (SO4). The "·5H2O" indicates that there are five water molecules associated with each formula unit of CuSO4.