72%
85%
25%
10%
there is 43% of water in the red blood cells
I cannot answer it,i need help
their isn't one CuSO4 is an anhydrous salt which will absorb water so the way to find out how much is in it is to find out the difference in water befor and after addition and calculate it by finding the mols of water absorbed incomplarison with the number of mols of CuSO4 used. it is normally wrighten nH2O. CuSO4
CuSO4•5H2O + heat ---> CuSO4 + 5H2O
No, the percent by mass of copper in CuSO4 5H2O will be different than in CuSO4 because CuSO4 5H2O includes water molecules in addition to the copper sulfate compound itself. Therefore, the total mass of CuSO4 5H2O will be greater, resulting in a lower percent by mass of copper in CuSO4 5H2O compared to CuSO4.
Hydrated copper sulfate, CuSO4·5H2O, contains 36.10% water by mass.
CuSO4.5H2O(s) --> CuSO4(s) + 5H2O(g)
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
The balanced equation for the heating of copper(II) sulfate pentahydrate (CuSO4•5H2O) is: CuSO4•5H2O(s) -> CuSO4(s) + 5H2O(g). This reaction decomposes the pentahydrate compound into anhydrous copper(II) sulfate and water vapor.
CuSO4 · 5H2O has 5 water molecules attached to each CuSO4 molecule.
CuSO4.5H2O === heat===> CuSO4 + 5H2O CuSO4.5H2O is the blue copper sulphate you have in a school chemistry lab. When you heat it, it turns white to CuSO4, as the heat drives off the water of crystallization. The analogy is like holding a ball(5H2O) in you hand(CuSO4). The ball is not part of you, but if your hand is 'twisted/(heated)' , then you let go of the ball.
The ratio of moles of CuSO4 to moles of water in CuSO4•5H2O is 1:5. This is because there is one mole of CuSO4 for every five moles of water in the compound.
Copper sulfatepentahydrate is a solid at 20 degrees Celsius has a density of 2.28g/cm3 (cubed)... and its' chemical symbol is CuSO4-5H2O
The structural formula of CuSO4·5H2O is Cu(H2O)4SO4, where the copper ion (Cu) is surrounded by four water molecules (H2O) and one sulfate ion (SO4). The "·5H2O" indicates that there are five water molecules associated with each formula unit of CuSO4.