23 x 53 = 1000
32 x 19
To express 160 in index form using prime factors, we first need to find the prime factors of 160. Breaking down 160 into its prime factors, we get 2^5 * 5. Therefore, in index form, 160 can be written as 2^5 * 5.
189 = 3 x 3 x 3 x 7 = 33 x 7
648 expressed as a product of its prime factors in index form is 2^3 times 3^4
To express 160 in index form using prime factors, we first need to find the prime factors of 160. Breaking down 160 into its prime factors, we get 2^5 * 5. Therefore, in index form, 160 can be written as 2^5 * 5.
23 x 53 = 1000
32 x 19
22 x 3 = 12
49/1000 can not be reduced because 7, the only prime factor of 49, is not a factor of 1000.
24 x 3 x 5 = 240.
It is: 2^4 times 3^2 = 144
It is: 23*3*52 = 600
Since the numerator of the fraction is prime and is not a factor of the denominator, the proper fraction 13/1000 is already expressed in its simplest form.
189 = 3 x 3 x 3 x 7 = 33 x 7
2√2×41 Two raised to the power two into forty one
Oh, what a happy little question! To find the prime factorization of 96, we break it down into its prime factors: 2 x 2 x 2 x 2 x 2 x 3. In index form, this would be written as 2^5 x 3. Keep on painting those mathematical landscapes, my friend!