23 x 53 = 1000
23 x 53 = 1000
32 x 19
189 = 3 x 3 x 3 x 7 = 33 x 7
648 expressed as a product of its prime factors in index form is 2^3 times 3^4
Well, isn't that just a happy little question! To write 160 as a product of its prime factors, we can express it as 2^5 * 5. In index form, this would be written as 2^5 * 5^1. Just remember, there are no mistakes, only happy little accidents in math!
23 x 53 = 1000
To express 375 in prime factor index form, first, factor it into its prime components. The prime factorization of 375 is (3 \times 5^3) because (375 = 3 \times 125) and (125 = 5^3). Therefore, the prime factor index form of 375 is (3^1 \times 5^3).
32 x 19
22 x 3 = 12
49/1000 can not be reduced because 7, the only prime factor of 49, is not a factor of 1000.
To express 375 in index form, we first factor it into its prime components. The prime factorization of 375 is (3 \times 5^3). Therefore, in index form, 375 can be written as (3^1 \times 5^3).
To express 375 in index form, we first need to factor it into its prime components. The prime factorization of 375 is (3 \times 5^3). Therefore, the index form of 375 can be written as (3^1 \times 5^3).
Since the numerator of the fraction is prime and is not a factor of the denominator, the proper fraction 13/1000 is already expressed in its simplest form.
It is: 23*3*52 = 600
To express 600 as a product of its prime factors in index form, we first find its prime factorization. The prime factors of 600 are 2, 3, and 5. Specifically, 600 can be expressed as (2^3 \times 3^1 \times 5^2). Thus, in index form, 600 is represented as (2^3 \times 3^1 \times 5^2).
2√2×41 Two raised to the power two into forty one
189 = 3 x 3 x 3 x 7 = 33 x 7