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Q: What is the prime factorization of 128 using exponents?

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As a product of its prime factors in exponents: 2^7 = 128

2^7

The prime factorization of 128 is: 2 x 2 x 2 x 2 x 2 x 2 x 2 or 27

128 64,2 32,2,2 16,2,2,2 8,2,2,2,2 4,2,2,2,2,2 2,2,2,2,2,2,2

2^7

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128 = 27

Prime factorization for 128 is 27

It is 2 and as a product of its prime numbers in exponents 2^7 = 128

27

128 = 27

As a product of its prime factors in exponents: 2^7 = 128

2^7

The prime factorization of 128 is: 2 x 2 x 2 x 2 x 2 x 2 x 2 or 27

128 64,2 32,2,2 16,2,2,2 8,2,2,2,2 4,2,2,2,2,2 2,2,2,2,2,2,2

2^7

27 = 128

Divid 128 repeatedly by the smallest prime numbers you can find until you get to 1. Like this:128 / 264 / 232 / 216 / 28 / 24 / 22 / 2You can see from this that the only prime factor of 128 is 2

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