What is the prime factorization of 225?

Answer 1

The prime factorization of 225 is 3 * 3 * 5 * 5 or 3^2 * 5^2.
To work out the prime factors of a number, it helps to divide it by obvious factors first. In this case, the number ends in a 5, so we know we can divide it by 5. Do this and we are left with 45. This is known from times tables to be 9x5, and 9 can be split up into 3 and 3. Thus we have finished prime factorizing 225. The prime factors of it are 5, 5, 3 and 3.
3 x 3 x 5 x 5 = 225

Answer 2

For a start, look at the last digit. Since it 5, the number is divisible by 5. Divide it by five, to get 5 x ... (some other factor). Continue looking for other prime factors in this remaining factor, until you only get prime numbers. (225 is also divisible by 3.)

Answer 3

225 = 3 x 3 x 5 x 5 or 32 x 52

Answer 4

The prime factors of 225 are: 3 x 3 x 5 x 5

Answer 5

Prime factors of 225 are 3 x 3 x 5 x 5.

Answer 6

225 = 3*3*5*5