The prime numbers from 1-6 are 2, 3, 5 (1 is not prime). There are 3 prime numbers on a dice and 6 total. therefore the probability of rolling a prime is 3/6. The probability of getting a tails when flipping a coin is 1/2. Therefore you just multiply the two.
3/6 * 1/2 = 1/4
The probability of getting at least one prime number in two dice is 3/4.
1 out of 2.
Since there are 3 prime numbers, 13, 17, and 19, in the range 12 to 19, the probability of throwing a prime number on a fair eight sided die numbered 12 to 19 is 3 in 8.
total numbers taht can be occure=1,2,3,4,5,6 prime number taht can occure in a roll= 2, 3,5 total sample space= n=6 total faverable cases= m=3 P(prime number)=m/n=3/6=1/2 probability of rolling a prime number is 1/2
there are (2, 3, 5) only 3 prime numbers on a single dice. 1 is not considered a prime number.
The probability is 0 since if both dice show the number 6, their sum is 12 which is not a prime.
The probability of getting at least one prime number in two dice is 3/4.
1 out of 2.
The probability of eventually throwing a prime number is 1. On a single throw, of a fair die, the probability is 1/2.
false.
If the numbers are 1 to 6, there are three prime numbers in that range, a probability of 50%.
50% 1/2 0.5
The probability is 1 out of two. The primes you can roll are 2,3, and 5.
it might be 395,652,150,468,457,125,279,456,000,000 chanch to roll a prime number when a monkey appeares at the door
Assuming you mean the sum of the two dice is a prime number, then: The possible outcomes are 2, 3, 5, 7, 11 which occur 1, 2, 4, 7, 2 times respectively. There are 36 possible outcomes → pr(prime_sum) = (1+2+4+7+2)/36 = 16/36 = 4/9 If you mean that both dice must show a prime number, then: The possible primes are 2, 3, 5 → probability of 1 die showing a prime number is 3/6 = ½ → probability both show a prime number is ½ × ½ = ¼ If you mean either or both dice could show a prime number, then: The possible primes are 2, 3, 5 → probability of 1 die showing a primes is 3/6 = ½ → probability of a die not showing a prime is 1 - ½ = ½ → probability of neither die showing a prime is ½ × ½ = ¼ → probability of either or both dice show a prime is 1 - ¼ = ¾
The probability is 5/12.
a three on a dice is 1/6 and aheads on a coin is 50%