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What else can I help you with?
Write an inequality for the product of 12 and a number is greater than36?
12n > 36 n > 3
Find two positive integers where one is 3 more than twice the other and their product is 90?
Let one integer be n, then the other is 2n + 3 and n(2n + 3) = 90; solve this last equation for n: n(2n + 3) = 90 ⇒ 2n2 + 3n - 90 = 0 ⇒ (2n + 15)(n - 6) = 0 ⇒ n = 6 or n = -7.5 As n must be a (positive) integer, the solution n = -7.5 can be ignored, leaving n = 6, giving 2n + 3 = 15. Thus the two positive integers are 6 and 15.
What is the unit's digits of the product of the first 21 prime numbers?
Oh, dude, you want to know the unit's digits of the product of the first 21 prime numbers? Well, let me casually tell you that the unit's digit of a product depends on the unit's digits of the numbers being multiplied. Since the unit's digit of all prime numbers greater than 5 is either 1, 3, 7, or 9, the product of the first 21 prime numbers will end in a unit's digit that is a result of multiplying these digits together. Cool, right?
If m and n are prime numbers such that the sum of m and n is greater than 20 and the product of m and n is less than 50 What is a possible value of the product of m and n?
38 or 46
What is the product of a number n and 12?
12 * n = 12n That is the best you can do without knowing what n is!
The product of a number and 3 is -21?
24
What is the power 3 as a product of the same factor?
n to the 3rd power is n x n x n
How do you write the product of 3 and n?
3n is the simplest, but you could also write it as 3*n or 3.n or 3xn. The problem with the last form is that it could represent the product of 3 and x and n.
3 less than the product of 4 and n?
The equation = 4n-3
What is the product of 3 and 6 more than a number?
3*(n+6)
For what values of n will the product 3n be less than a 50?
3n < 50 if 3n/3 < 50/3 that is, if n < 50/3 = 162/3.
What is the product of a9 times a3?
The product of ( a^9 ) times ( a^3 ) can be calculated using the property of exponents that states ( a^m \times a^n = a^{m+n} ). Therefore, ( a^9 \times a^3 = a^{9+3} = a^{12} ).
Why is the product of 3 consecutive integers always divisible by 6?
Let the three integers be, n, (n + 1), and (n + 2) Then at least one of these numbers is even and therefore has a factor of 2. And one of the numbers is divisible by 3 **. Therefore the product has factors of 2 and 3 and is thus divisible by 2 x 3 = 6. ** Either n is divisible by 3. Or, n leaves a remainder of 1 when divided by 3 in which case (n + 2) is divisible by 3. Or, n leaves a remainder of 2 when divided by 3 in which case (n + 1) is divisible by 3.
Best represents the product of two consecutive integers?
The product of two consecutive integers can be represented mathematically as ( n(n + 1) ), where ( n ) is any integer. This expression captures the idea that the two integers are ( n ) and ( n + 1 ). For example, if ( n = 3 ), the product would be ( 3 \times 4 = 12 ). This representation highlights the relationship between consecutive numbers in a simple algebraic form.
What is the power of the product of the same factor then find the value?
The power of a product states that when you raise a product of factors to a power, you can distribute the exponent to each factor. Mathematically, this is expressed as ((ab)^n = a^n \times b^n). If you have the same factor, such as (a), the expression ((a^m)^n) simplifies to (a^{m \cdot n}). For example, if (a = 2), (m = 3), and (n = 2), then ((2^3)^2 = 2^{3 \cdot 2} = 2^6 = 64).
What are the release dates for A-N-T- Farm - 2011 Product MisplacemANT 3-9?
A-N-T- Farm - 2011 Product MisplacemANT 3-9 was released on: USA: 20 September 2013
What is the value of n(n-1)(n-2)(n-3)(n-4)(n-5) in a given mathematical expression or equation?
The value of the expression n(n-1)(n-2)(n-3)(n-4)(n-5) is the product of n, n-1, n-2, n-3, n-4, and n-5.
