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Write an inequality for the product of 12 and a number is greater than36?
12n > 36 n > 3
What is the unit's digits of the product of the first 21 prime numbers?
Oh, dude, you want to know the unit's digits of the product of the first 21 prime numbers? Well, let me casually tell you that the unit's digit of a product depends on the unit's digits of the numbers being multiplied. Since the unit's digit of all prime numbers greater than 5 is either 1, 3, 7, or 9, the product of the first 21 prime numbers will end in a unit's digit that is a result of multiplying these digits together. Cool, right?
Find two positive integers where one is 3 more than twice the other and their product is 90?
Let one integer be n, then the other is 2n + 3 and n(2n + 3) = 90; solve this last equation for n: n(2n + 3) = 90 ⇒ 2n2 + 3n - 90 = 0 ⇒ (2n + 15)(n - 6) = 0 ⇒ n = 6 or n = -7.5 As n must be a (positive) integer, the solution n = -7.5 can be ignored, leaving n = 6, giving 2n + 3 = 15. Thus the two positive integers are 6 and 15.
If m and n are prime numbers such that the sum of m and n is greater than 20 and the product of m and n is less than 50 What is a possible value of the product of m and n?
38 or 46
What is the product of a number n and 12?
12 * n = 12n That is the best you can do without knowing what n is!
