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Express 120 as the product of powers of its prime factors?
It is: 23*31*51 = 120
What is the prime factorization of 120 ordered from least to greatest?
As a product of its prime factors: 2*2*2*3*5 = 120
Why does 2x3x4x5 give you the least number of factors?
The expression 2x3x4x5 can be simplified to 120. The number 120 has the least number of factors because it is a product of consecutive prime numbers (2, 3, and 5). When a number is a product of distinct prime numbers, it will have fewer factors compared to numbers with repeated prime factors. In this case, 120 only has 16 factors, making it the least among numbers with the same number of prime factors.
Express 120 as the product of its prime factors give the answer in index form?
120 = 23 x 3 x 5
What are the prime factors of 120 as a product?
2 x 2 x 2 x 3 x 5 = 120
How do write a number for example 120 as a product of its prime factors and give answers in index notation?
As a product of its prime factors: 23*3*5 = 120
What is the prime factoication of 120?
As a product of its prime factors: 2*2*2*3*5 = 120 or as 23*3*5 = 120
What are the prime fatorization of 120?
As a product of its prime factors: 2*2*2*3*5 = 120 or as 23*3*5 = 120
Express 120 as the product of powers of its prime factors?
It is: 23*31*51 = 120
What is the prime factorization of 120 using a factor tree?
As a product of its prime factors: 2*2*2*3*5 = 120
What is the prime factorization of 120 ordered from least to greatest?
As a product of its prime factors: 2*2*2*3*5 = 120
Why does 2x3x4x5 give you the least number of factors?
The expression 2x3x4x5 can be simplified to 120. The number 120 has the least number of factors because it is a product of consecutive prime numbers (2, 3, and 5). When a number is a product of distinct prime numbers, it will have fewer factors compared to numbers with repeated prime factors. In this case, 120 only has 16 factors, making it the least among numbers with the same number of prime factors.
What is the prime factors for 120?
The prime factors of 120 are: 2,3,5
How do you find the prime factorization of 120 using exponents?
As a product of its prime factors using exponents: 2^3 times 3 times 5 = 120
Express 120 as the product of its prime factors give the answer in index form?
120 = 23 x 3 x 5
What are the prime factors of 120 as a product?
2 x 2 x 2 x 3 x 5 = 120
Express 120 as a product of its prime factors?
2 x 2 x 2 x 3 x 5 = 120
