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The ratio of NaHCO3 to WHAT!

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What is the ratio between NaHCO3 and NaCl?

The molar mass of sodium chloride is 58,44 g. The molar mass of sodium bicarbonate is 84,007 g. The ratio is 1,437.


If 2.10 g of NaHCO3 are decomposed then how many grams of water are produced?

NaHCO3 ----> H2O Mass 2.10g 0.045g RAM 84 g/moles 18 g/moles number of moles 0.025moles 0.025moles


What mass of C6H8O7 is needed to consume 0.42g of NaHCO3?

To find the mass of C6H8O7 needed to consume 0.42g of NaHCO3, you first need to balance the chemical equation for the reaction between them. Then, calculate the molar ratio between NaHCO3 and C6H8O7 to determine the mass needed. This involves stoichiometry and molar mass calculations to find the answer.


Is nahco3 a element compound?

No, NaHCO3 is not an element, it is a compound. It is the chemical formula for sodium bicarbonate, which is commonly known as baking soda. It is composed of sodium (Na), hydrogen (H), carbon (C), and oxygen (O) atoms bonded together in a specific ratio.


Chemical formula for sodium hydrogencarbonate?

The answer is NaHCO3


What mass of NaHCO3 would be needed to neutralize a spill consisting of 12.5 mL of 5.0 M HCl?

12.5 mL * 5.0 (m)mol/(m)L HCl = 62.5 mmol spilled HClneeds62.5 mmol NaHCO3 = 62.5 mmol * 84.01 (m)g/(m)mol NaHCO3 = 5250 mg NaHCO3 = 5.25 g pure NaHCO3


How many moles of NaHCO3 are present in a 6.10 g sample?

Divide 6.10 (g NaHCO3) by 84.007 (g.mol−1 NaHCO3) to get 0.0726 mol NaHCO3


What mass of NaHCO3 is needed to neutralize 150ml of 044M HCl?

Several part problem. Get molarity of NaHCO3. (150 ml)( M NaHCO3) = (150 ml)(0.44 M HCl) = 0.44 M NaHCO3 --------------------------- get moles NaHCO3 ( 150 ml = 0.150 Liters ) 0.44 M NaHCO3 = moles NaHCO3/0.150 Liters = 0.066 moles NaHCO3 ---------------------------------------get grams 0.066 moles NaHCO3 (84.008 grams/1 mole NaHCO3) = 5.54 grams NaHCO3 needed ---------------------------------------------answer


What is NaHCO3 commonly called?

NaHCO3 is commonly called bicarbonate of soda or baking soda.


How many moles are in 2.10 kg of NaHCO3?

For this you need the atomic (molecular) mass of NaHCO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaHCO3=84.0 grams110 grams NaHCO3 / (84.0 grams) = 1.31 moles NaHCO3


Nahco3 ch3co2 na ch3co2 CO2 h20 what mass of nach3co2 can be obtained from mixing 15.0 grams of nahco3 with 125ml of 15 m ch3co2h?

To determine the mass of NaCH3CO2 obtained, first calculate the amount of CH3CO2H in moles using its molarity and volume. Then use the stoichiometry of the reaction to find the moles of NaHCO3 reacting. Finally, use the mole ratio between NaHCO3 and NaCH3CO2 to find the mass of NaCH3CO2 that can be obtained.


What is the percent CO2 in sodium bicarbonate?

Sodium Bicarbonate come from absorption of CO2 into NaOH Total reaction is 2NaOH + CO2 -> NaHCO3 + H2O Each mole of NaHCO3 come from absorption of 1 mole CO2 Molecular weight of NaHCO3 is 84 g/mol and CO2 is 44 g/mol It is that 84 g of NaHCO3 had 44 g of CO2 By weight ratio it is 52% CO2 in Sodium Bicarbonate.