answersLogoWhite

0


Best Answer

The ratio of NaHCO3 to WHAT!

User Avatar

Wiki User

10y ago
This answer is:
User Avatar
More answers
User Avatar

Anonymous

Lvl 1
4y ago

no one knows

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What is the ratio of NaHCO3?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What is the ratio between NaHCO3 and NaCl?

The molar mass of sodium chloride is 58,44 g. The molar mass of sodium bicarbonate is 84,007 g. The ratio is 1,437.


If 2.10 g of NaHCO3 are decomposed then how many grams of water are produced?

When 2.10 g of NaHCO3 decomposes, it produces CO2, H2O, and Na2CO3. The molar ratio between NaHCO3 and H2O is 1:1. This means that 2.10 g of NaHCO3 will produce 18 g of water.


What mass of C6H8O7 is needed to consume 0.42g of NaHCO3?

To find the mass of C6H8O7 needed to consume 0.42g of NaHCO3, you first need to balance the chemical equation for the reaction between them. Then, calculate the molar ratio between NaHCO3 and C6H8O7 to determine the mass needed. This involves stoichiometry and molar mass calculations to find the answer.


Is nahco3 a element compound?

No, NaHCO3 is not an element, it is a compound. It is the chemical formula for sodium bicarbonate, which is commonly known as baking soda. It is composed of sodium (Na), hydrogen (H), carbon (C), and oxygen (O) atoms bonded together in a specific ratio.


Chemical formula for sodium hydrogencarbonate?

The chemical formula for sodium hydrogen carbonate is NaHCO3.


What mass of NaHCO3 would be needed to neutralize a spill consisting of 12.5 mL of 5.0 M HCl?

To neutralize the HCl spill, we need to determine the amount of moles of HCl present first. The moles of HCl can be calculated as concentration (mol/L) x volume (L). Then, since NaHCO3 reacts in a 1:1 ratio with HCl, you would need the same number of moles of NaHCO3 as moles of HCl to neutralize the spill. From there, you can calculate the mass of NaHCO3 needed using its molar mass.


How many moles of NaHCO3 are present in a 6.10 g sample?

Divide 6.10 (g NaHCO3) by 84.007 (g.mol−1 NaHCO3) to get 0.0726 mol NaHCO3


What mass of NaHCO3 is needed to neutralize 150ml of 044M HCl?

To neutralize 150 mL of 0.44 M HCl, you would need an equal number of moles of NaHCO3. First, calculate the number of moles of HCl (mol = Molarity x Volume) used. Then, since 1 mol of NaHCO3 neutralizes 1 mol of HCl, you would need the same number of moles of NaHCO3. From that, you can calculate the mass of NaHCO3 needed using its molar mass.


What is the percent CO2 in sodium bicarbonate?

Sodium Bicarbonate come from absorption of CO2 into NaOH Total reaction is 2NaOH + CO2 -> NaHCO3 + H2O Each mole of NaHCO3 come from absorption of 1 mole CO2 Molecular weight of NaHCO3 is 84 g/mol and CO2 is 44 g/mol It is that 84 g of NaHCO3 had 44 g of CO2 By weight ratio it is 52% CO2 in Sodium Bicarbonate.


Nahco3 ch3co2 na ch3co2 CO2 h20 what mass of nach3co2 can be obtained from mixing 15.0 grams of nahco3 with 125ml of 15 m ch3co2h?

To determine the mass of NaCH3CO2 obtained, first calculate the amount of CH3CO2H in moles using its molarity and volume. Then use the stoichiometry of the reaction to find the moles of NaHCO3 reacting. Finally, use the mole ratio between NaHCO3 and NaCH3CO2 to find the mass of NaCH3CO2 that can be obtained.


What is NaHCO3 commonly called?

NaHCO3 is commonly called bicarbonate of soda or baking soda.


How many moles are in 2.10 kg of NaHCO3?

For this you need the atomic (molecular) mass of NaHCO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaHCO3=84.0 grams110 grams NaHCO3 / (84.0 grams) = 1.31 moles NaHCO3