9(2 + 3)
(2 x 9) + (3 x 9) = 5 x 9 = 45
40 + 44 = (4 x 10) + (4 x 11) = 4 x 21 = 84
18 + 24 = (3 x 6) + (4 x 6) = 7 x 6 = 42
The GCF is 18.
The GCF of 18 and 36 is 18.
The GCF in this case is 3. 75 + 18 = 93 93/3 = 31 Rewriting 31 as another sum seems unnecessary, but sure. (30+1) * 3 = 93 = 75 + 18.
(2 x 9) + (3 x 9) = 5 x 9 = 45
6 + 36
"The sum of a number and three times another number is 18. find the numbers if their product is a maximum?"
It is a direct result based on the distributive property of multiplication over addition. GCF(18, 27) = 9So 18 + 27 = 9*2 + 9*3 = 9*(2+3) = 9*5 = 45
It is 9*(2 + 3)
It can be either
40 + 44 = (4 x 10) + (4 x 11) = 4 x 21 = 84
(2 x 9) + (3 x 9) = 5 x 9 = 45
product
Product of two numbers a and b = LCM(a,b) x GCF(a,b)...(1)Here, product of 18 and 360 = 6480Now, we shall find GCF of 18 and 360 by using the method of prime factorization.Prime factorization of 18 = 2x3x3Prime factorization of 360 = 2x2x2x3x3x5It is clear from the prime factorization that gcf = 18Now using (1) we can find LCM:LCM(18,360) = Product of 18 and 360/GCF(18,360) = 6480/18 = 360So, LCM and GCF of 18 & 360 is 360 and 18.Also, it is important to note that 360 is divisible by 18 then GCF is 18 and LCM is 360.
18 and 8127 and 7236 and 6345 and 54