The sum of any one number is the value of that number.
None of the items in the list.
To write decimal 0.24 in expanded form, you would express it as the sum of its place values. In this case, 0.24 can be expanded as (2 x 0.1) + (4 x 0.01). This breaks down the decimal number into its individual digits multiplied by their respective place values.
5.8
The sum_of_a_series = 1/2 x number_in_series x (first_number + last_number) The first odd number is 2 x 1 - 1 = 1, the 55th odd number is 2 x 55 - 1 = 109 Sum = 1/2 x 55 x (1 + 109) = 1/2 x 55 x 110 = 552 = 3025 It can be seen that the sum of the first n consecutive odd numbers is always n2: sum = n/2(1 + (2n - 1)) = n/2(2n) = n2
301.09
0.48 :):):):):):):):):):):):):):)*********************** i rock sam sum mah kam nas
Yes. One such example 0.12 + 0.38 = 0.5
Expressed as a decimal, 7 3/100 is equal to 7.03.
To add the decimal numbers 1.50 and 3.25, you align the decimal points and then add the numbers as if they were whole numbers. 1.50 + 3.25 = 4.75 Therefore, the sum of 1.50 and 3.25 is 4.75.
The sum is: 1+109 = 110
It is: 14/100 plus 14/10 = 77/50 in its simplest form or 1.54 as a decimal
To do this you first need to write 45 hundredths as a decimal. This will be 45x0.01 or 0.45. Then to complete the sum you just add that to 4.132: 4.132+0.45 = 4.582 Therefore, 45 hundredths more than 4.132 is 4.582
No, the sum of a repeating decimal and a terminating decimal is never a terminating decimal.
0.47
50.04
They are: 7.53 and 6.08 rounded to the nearest hundredths respectively As a sum, 13.60