the sum of (1001+1010)is=(10011)
Lets do the binary addition of the numbers given that is , 1010 and 1101 that can be written as : 1010 +1101 ----------- (1 is carry)1 1 11. ------------
This kind of question is frequently asked and easily solved. 1 + 1000 = 1001 2 + 999 = 1001 3 + 998 = 1001 You can see the developing pattern here. Taking integers in order from the top and bottom of the list allows you to create hundreds of equal sums. The last such sum that can be made is 500 + 5001 = 1001. It is clear that you then have 500 sums, each equal to 1001. 1001 X 500 = 500,500 which is the sum of all the integers combined.
The average of a group of numbers is equal to the sum of the numbers divided by the number of numbers. If you want to find the sum of the five numbers, just multiply 790.6 by 5 to get the sum, which is 3953
You can't write that as the sum of two prime numbers. Note: Goldbach's Conjecture (for expressing numbers as the sum of two prime numbers) applies to EVEN numbers.
The sum of the first 50 natural numbers is 1,251.
1110
Written as a binary number, 10 + 101 + 1010 = 10001.
Lets do the binary addition of the numbers given that is , 1010 and 1101 that can be written as : 1010 +1101 ----------- (1 is carry)1 1 11. ------------
The sum of 1,011 and 1,001 is 2,012. Unless they are binary numbers, in which case 1011 + 1001 = 10100
easy, 1011. in binary of course. convert 1011 binary to decimal you get 11.
10011.
The sum of binary numbers is also a binary number.
1001
To find the sum of two binary numbers, we can add them together just like decimal numbers. Starting from the rightmost bit, we add each pair of bits along with any carry from the previous addition. In this case, 1+0=1, 1+1=0 with a carry of 1, 0+1=1 with the carry, and 1+1+1=1 with a carry. Therefore, the sum of 1011 and 1010 in binary is 10101.
Oh, dude, you want me to find 4-digit numbers where the digits add up to 2? That's like finding a needle in a haystack! But hey, I'm up for the challenge. The only number that fits the bill is 1001. So, there you go, one lonely 4-digit number with a digit sum of 2.
The sum of all palindromic numbers from 1001 to 9999 is 495000.
It is 11011.