the sum of (1001+1010)is=(10011)
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Lets do the binary addition of the numbers given that is , 1010 and 1101 that can be written as : 1010 +1101 ----------- (1 is carry)1 1 11. ------------
This kind of question is frequently asked and easily solved. 1 + 1000 = 1001 2 + 999 = 1001 3 + 998 = 1001 You can see the developing pattern here. Taking integers in order from the top and bottom of the list allows you to create hundreds of equal sums. The last such sum that can be made is 500 + 5001 = 1001. It is clear that you then have 500 sums, each equal to 1001. 1001 X 500 = 500,500 which is the sum of all the integers combined.
The average of a group of numbers is equal to the sum of the numbers divided by the number of numbers. If you want to find the sum of the five numbers, just multiply 790.6 by 5 to get the sum, which is 3953
You can't write that as the sum of two prime numbers. Note: Goldbach's Conjecture (for expressing numbers as the sum of two prime numbers) applies to EVEN numbers.
The sum of the first 50 natural numbers is 1,251.