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the sum of (1001+1010)is=(10011)

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10101

Q: What is the sum of the binary numbers 1001 and 1010?

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Lets do the binary addition of the numbers given that is , 1010 and 1101 that can be written as : 1010 +1101 ----------- (1 is carry)1 1 11. ------------

This kind of question is frequently asked and easily solved. 1 + 1000 = 1001 2 + 999 = 1001 3 + 998 = 1001 You can see the developing pattern here. Taking integers in order from the top and bottom of the list allows you to create hundreds of equal sums. The last such sum that can be made is 500 + 5001 = 1001. It is clear that you then have 500 sums, each equal to 1001. 1001 X 500 = 500,500 which is the sum of all the integers combined.

The average of a group of numbers is equal to the sum of the numbers divided by the number of numbers. If you want to find the sum of the five numbers, just multiply 790.6 by 5 to get the sum, which is 3953

You can't write that as the sum of two prime numbers. Note: Goldbach's Conjecture (for expressing numbers as the sum of two prime numbers) applies to EVEN numbers.

The sum of the first 50 natural numbers is 1,251.

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1110

Written as a binary number, 10 + 101 + 1010 = 10001.

Lets do the binary addition of the numbers given that is , 1010 and 1101 that can be written as : 1010 +1101 ----------- (1 is carry)1 1 11. ------------

1001 1010 1100 they all are

The sum of 1,011 and 1,001 is 2,012. Unless they are binary numbers, in which case 1011 + 1001 = 10100

easy, 1011. in binary of course. convert 1011 binary to decimal you get 11.

10011.

The sum of binary numbers is also a binary number.

1001

I put leading zeros, so everything will line up:01011 (which is eleven)01010 (which is ten)=====10101 (which is twenty one). The rightmost column is 1+0=1. The next column is 1+1=102. Carry the 1 and you have 1 + 0 + 0 = 1. Then 1+1=102, then carry that 1 for the most significant digit.

The sum of all palindromic numbers from 1001 to 9999 is 495000.

11011