The sum_of_a_series = 1/2 x number_in_series x (first_number + last_number)
The first odd number is 2 x 1 - 1 = 1, the 55th odd number is 2 x 55 - 1 = 109
Sum = 1/2 x 55 x (1 + 109)
= 1/2 x 55 x 110
= 552
= 3025
It can be seen that the sum of the first n consecutive odd numbers is always n2:
sum = n/2(1 + (2n - 1))
= n/2(2n)
= n2
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4225
You can use one of the formulae for the sum of an arithmetic progression to calculate that.
9 and 11
The sum of the first 100 odd numbers is 10,000.
The numbers are 43 and 45.