It depends on which test is used.
Since the requirements for Mensa membership are that you be in the top 2% of the IQ range, you can get specifics by looking at the membership requirements page of the Mensa website (see 'related links').
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an IQ of 132 in SD (standard deviation) of 16 and 130 in a SD of 15 , this mean top 2% of world's population according to the bell curve..for more info , search in google.
The requirement is 140 on a standard IQ test. That would be the top 98th percentile.
''Above plant life at least.'' QUOTE. ^^ Not particularly helpful, is it? To qualify for Mensa you have to be in the top 2% of the population, IQ-wise. There is a MENSA test you can take to see whether you qualify or you could take a different IQ test for example CattellB-III. I hope that this helps with your enquiries.
95 You cannot tell your IQ correctly by answering 8 questions. If you really want to know your IQ get tested by a professional. Theese online IQ tests are a complete waste of time.
To convert a fraction to percent, divide the numerator (which also means top number) by the denominator (which also means bottom number). Example: To convert the fraction 3/4 to percent, divide 3 (top number) by 4 (bottom number) and the answer is.75. To convert to percent, move the decimal 2 steps to the right and insert the percent sign on the end: .75 = 75%