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"Still" implies that the original number is a square number. In that case, the answer is as follows:

There is no number such that it is a perfect sqiuare and that the number increased (or decreased) by 10 is also a perfect square.

And if you do not limit it to perfect square then every non-negative number is a square with the number that is 10 more also being a square.

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Q: What number can be increased or decreased by 10 and you will still have a square number?
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Sure. Let's take an example with numbers instead of variables. 8/9 is a rational number - the ratio of two integers. If you square it, you get (8/9)2 = 82/92 = 64/81; that is, if you square each integer, you get an integer again. Therefore, the resulting number is rational again - a number that can be expressed as the ratio of two integers. Replace with any other integers; you will still have a ratio of integers if you square it.


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The square root of -121 is imaginary. It has value of i11.It is not rational, irrational, nor real. The coefficient of i, 11, is real and rational, but the result of multiplying i by 11 is imaginary.Now, The Coefficient of (i11) is a complex number, because when dealing with i, the true form is the square root of -1, and so this also means that you still have 2 answers, positive and negative i11, and so the square root of -121 is imaginary, or complex rational number. But, because it is complex, it is not truly rational, all this means is that you end up with aninteger in your complex answer. So, To answer your question, the answer is non of the above, just imaginary. and the value is plus or minus (i11).

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