how do you solve the questions to this sequence 0, 10, 24, 56, 112, 190
(1) Find the difference of the two previous numbers in the sequence. (2) Add 6 to this difference. (3) Take the number from step 2 and add it to the last number in the sequence to find the next number. For example, to find the next number in the sequence. (1) 112 - 77 = 35 (2) 35 + 6 = 41 (3) 112 + 41 = 153
112 358 1221 3885 other possibilities exist.
280
2121
Ascending terms in the sequence are equal to 12, 32, 52, __, 92, and, for some reason, 102, not 112. Therefore, assuming the last term in the sequence to be 112 = 121, the fourth term in the sequence is 72 = 49.
112 = 121122 = 144 is your answer
311
== 49 == 144 = 122 121 = 112 100 = 102 81 = 92 64 = 82 Implies 122, 112, 102, 92, 82 So the next number should be 72 = 49. So, the next number is 49.
To find the missing number in the sequence 32, 52, 74, 112, 135, we need to identify the pattern or rule governing the sequence. The differences between consecutive numbers are 20, 22, 38, and 23, respectively. The pattern is not immediately clear, but it appears that the differences are not following a simple arithmetic progression. One possible explanation could be that the differences are increasing by odd numbers (2, 16, 15), so the next difference could be 15. Adding 15 to the last number in the sequence (135) gives us 150 as a potential missing number.
222. To get from 5 to 12, we add 7. To get from 12 to 26, we add 14. To get from 26 to 54, we add 28. To get from 54 to 110, we add 56. The number added is doubling each time. So next time we need to add 112 (56*2), so the next number in the sequence is 222.
Either (a) multiply 112 by 0, by 1, by 2, etc., or (b) starting with zero, add 112 repeatedly to get the following numbers in the sequence of multiples.
121As 100 = 102 then the next largest square number will have to be 112 which is equal to 121.