how do you solve the questions to this sequence 0, 10, 24, 56, 112, 190
(1) Find the difference of the two previous numbers in the sequence. (2) Add 6 to this difference. (3) Take the number from step 2 and add it to the last number in the sequence to find the next number. For example, to find the next number in the sequence. (1) 112 - 77 = 35 (2) 35 + 6 = 41 (3) 112 + 41 = 153
112 358 1221 3885 other possibilities exist.
112 = 121122 = 144 is your answer
Ascending terms in the sequence are equal to 12, 32, 52, __, 92, and, for some reason, 102, not 112. Therefore, assuming the last term in the sequence to be 112 = 121, the fourth term in the sequence is 72 = 49.
311
== 49 == 144 = 122 121 = 112 100 = 102 81 = 92 64 = 82 Implies 122, 112, 102, 92, 82 So the next number should be 72 = 49. So, the next number is 49.
54 + 58 = 112
Either (a) multiply 112 by 0, by 1, by 2, etc., or (b) starting with zero, add 112 repeatedly to get the following numbers in the sequence of multiples.
112 is composite.
222. To get from 5 to 12, we add 7. To get from 12 to 26, we add 14. To get from 26 to 54, we add 28. To get from 54 to 110, we add 56. The number added is doubling each time. So next time we need to add 112 (56*2), so the next number in the sequence is 222.
121As 100 = 102 then the next largest square number will have to be 112 which is equal to 121.
Adding all integers from 33 to 112 inclusive gives you 5800.