They are rational numbers
Yes, it is a repeating decimal. Terminating and repeating decimals are rationals. Rational numbers can also be expressed as a fraction. 0.313131 is a repeating decimal.
Decimal numbers that end or recur are known as terminating or repeating decimals. 0.75 is a terminating decimal. 0.4444 repeating is a repeating decimal.
Yes, they are and that is because any terminating or repeating decimal can be expressed in the form of a ratio, p/q where p and q are integers and q is non-zero.
Repeating decimal. * * * * * It depends on the numbers! For example, 0.6 < 0.66... < 0.67 By the first inequality the repeatiing decimal is bigger, by the second the terminating one is bigger.
Yes, negative decimal numbers are rational, as long as it is terminating or repeating.
Rational numbers can be expressed as a terminating or repeating decimal.
fractions or decimals
Irrational numbers are numbers that cannot be expressed as a ratio of two integers or as a repeating or terminating decimal.
Yes, it is a repeating decimal. Terminating and repeating decimals are rationals. Rational numbers can also be expressed as a fraction. 0.313131 is a repeating decimal.
No, irrational numbers can't be expressed as a terminating decimal.
They are rational numbers.
irrational numbers
Decimal numbers that end or recur are known as terminating or repeating decimals. 0.75 is a terminating decimal. 0.4444 repeating is a repeating decimal.
They are both rational numbers.
Yes, they are and that is because any terminating or repeating decimal can be expressed in the form of a ratio, p/q where p and q are integers and q is non-zero.
In fact, the statement is true. Consequently, there is not a proper counterexample. The fallacy is in asserting that a terminating decimal is not a repeating decimal. First, there is the trivial argument that any terminating decimal can be written with a repeating string of trailing zeros. But, Cantor or Dedekind (I can't remember which) proved that any terminating decimal can also be expressed as a repeating decimal. For example, 2.35 can be written as 2.3499... Or 150,000 as 149,999.99... Thus, a terminating decimal becomes a recurring decimal. As a consequence, all real numbers can be expressed as infinite decimals. And that proves closure under addition.
Yes.