Yes, it is a repeating decimal. Terminating and repeating decimals are rationals. Rational numbers can also be expressed as a fraction. 0.313131 is a repeating decimal.
Yes, they are and that is because any terminating or repeating decimal can be expressed in the form of a ratio, p/q where p and q are integers and q is non-zero.
Decimal numbers that end or recur are known as terminating or repeating decimals. 0.75 is a terminating decimal. 0.4444 repeating is a repeating decimal.
Repeating decimal. * * * * * It depends on the numbers! For example, 0.6 < 0.66... < 0.67 By the first inequality the repeatiing decimal is bigger, by the second the terminating one is bigger.
Rational numbers - can be expressed as a fraction, and can be terminating and repeating decimals. Irrational numbers - can't be turned into fractions, and are non-repeating and non-terminating. (like pi)
Rational numbers can be expressed as a terminating or repeating decimal.
fractions or decimals
Irrational numbers are numbers that cannot be expressed as a ratio of two integers or as a repeating or terminating decimal.
Yes, it is a repeating decimal. Terminating and repeating decimals are rationals. Rational numbers can also be expressed as a fraction. 0.313131 is a repeating decimal.
No, irrational numbers can't be expressed as a terminating decimal.
They are rational numbers.
irrational numbers
Yes, they are and that is because any terminating or repeating decimal can be expressed in the form of a ratio, p/q where p and q are integers and q is non-zero.
Decimal numbers that end or recur are known as terminating or repeating decimals. 0.75 is a terminating decimal. 0.4444 repeating is a repeating decimal.
They are both rational numbers.
In fact, the statement is true. Consequently, there is not a proper counterexample. The fallacy is in asserting that a terminating decimal is not a repeating decimal. First, there is the trivial argument that any terminating decimal can be written with a repeating string of trailing zeros. But, Cantor or Dedekind (I can't remember which) proved that any terminating decimal can also be expressed as a repeating decimal. For example, 2.35 can be written as 2.3499... Or 150,000 as 149,999.99... Thus, a terminating decimal becomes a recurring decimal. As a consequence, all real numbers can be expressed as infinite decimals. And that proves closure under addition.
Yes.