12.5 percent is already round to the nearest tenth of a percent.
0.1%
82%
To round 66.66 percent to the nearest tenth of a percent, we look at the digit in the thousandths place, which is 6 in this case. Since 6 is greater than or equal to 5, we round the tenths place up by 1. Therefore, 66.66 percent rounded to the nearest tenth is 66.7 percent.
0.1%
All offspring will be short and round because the TtRr parent is heterozygous at both loci. This means all offspring will inherit one dominant allele for each trait (T and R), resulting in a short and round phenotype.
60%
100%
In a trihybrid cross, the offspring would inherit one allele from each parent for each of the three traits (Tall, green, and round). Since the parents are homozygous for all traits (ttggrr x ttggrr), all the offspring would be tall, green, and round, resulting in 100% of the offspring being tall, green, and round.
It does.. But you knew anything you would try to answer it 👏
The offspring will likely exhibit the tall phenotype due to the dominance of the tall allele. The genotype of the offspring would be TtRr, with a combination of dominant and recessive alleles for both height and seed shape. This type of cross would result in a 9:3:3:1 ratio of phenotypes in the offspring according to Mendelian genetics.
9082
It depends on the genetics of the parents. If both parents carry a short gene, then all the offspring would have a chance of being short. If only one parent carries the short gene, then approximately half of the offspring would be short.
12.5 percent is already round to the nearest tenth of a percent.
no. in the second generation it will have a short offspring , but in the first generation it will have tall offspring
A. Offspring with heterozygous genotype 100 percent B. Offspring with homozygous dominant genotype 0 percent C. Offspring with at least one copy of recessive gene 50 percent
You could round 27% to the nearest 5% and get 25%.