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Molar Mass of Al: 2(27.0g/mol) = 54.0g/mol

Molar Mass of O: 3(16.0g/mol) = 48.0g/mol

Molar Mass of compound: 102.0g.mol

(54.0g/mol / 102.0g/mol) x 100% = 52.9%

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Q: What percentage composition of Al2O3 is aluminum?
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Aluminum oxide (Al2O3) is composed of two aluminum atoms and three oxygen atoms. The molar mass of aluminum is 26.98 g/mol, and the molar mass of oxygen is 16.00 g/mol. Therefore, the percentage of aluminum in aluminum oxide is calculated as (2*26.98 g / 101.96 g) * 100%, which is approximately 52.9%.


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