it is not irrational. This is because there are two non irrational numbers that divide each other that are rational. So 10.46 is rational.
Yes. sqrt(18)/sqrt(2) = 3*sqrt(2) / sqrt(2) = 3
If you add, subtract or multiply rational numbers, the result will be a rational number. It will also be so if you divide by a non-zero rational number. But division by zero is not defined.
No. 4 root 2 and 2 root 2 are both irrational. Divide the first by the second you get 2. Which is not a member of the set of irrational numbers.
No, because you cannot divide by zero.
it is not irrational. This is because there are two non irrational numbers that divide each other that are rational. So 10.46 is rational.
No. If x is irrational, then x/x = 1 is rational.
Yes.
All fractions are rational numbers because irrational numbers can't be expressed as fractions
It is not always irrational.
yes, it is rational because it isnt neverending. irrational numbers are neverending like pi which is 3.14-----------------------------------. it basically never ends. rationals such as 25 over 100 end if you divide 100 into 25. sources: my algebra book
yes because two rational numbers divide to get that number. Wich are for example 27/-2, therefore -13.5 is rational.
The simplest example (of infinitely many) is probably the squareroot of two multiplied by itself equals two. Take any rational number, say 4.177 and divide it with any irrational number, say the square root of 13, and you will get a new irrational number. The product of your two irrational numbers now make a rational number.
If you divide a rational number by an irrational number, or vice versa, you will ALMOST ALWAYS get an irrational result. The sole exception is if you divide zero (which is rational) by any irrational number.
Yes, but only if the starting rational number is 0.
You can divide 65 by rationals and irrationals: Divided by a rational: 65 ÷ 13/2 = 10 Divided by an irrational: 65 ÷ √13 = 5√13
The answer requires a bit of mathematics, but goes like this:The product of any 2 rational numbers is a rational number.The product of any 2 irrational number is an irrational number.The product of a rational and an irrational number is an irrational number!Therefore simple logic tells us that there are more irrational numbers than rational numbers. There is a way to structure this mathematically, and I believe it is called an "Inductive Proof".Interesting !I'm going to say "No".I reason thusly:-- For every rational number 'N', you can multiply or divide it by 'e', add it to 'e',or subtract it from 'e', and the result is irrational.-- You can multiply or divide it by (pi), add it to (pi), or subtract it from (pi),and the result is irrational.-- You can take its square root, and more times than not, its square root is irrational.There may be others that didn't occur to me just now. But even if there aren't,here are a bunch of irrational numbers that you can make from every rational one.This leads me to believe that there are more irrational numbers than rational ones.-------------------------------------------------------------------------------------------------------There are infinitely many more irrationals than rationals; this was proved by G. Cantor (born 1845, died 1918). His proof is basically:The rational numbers can be listed by assigning to each of the counting numbers (1, 2, 3,...) one of the rational numbers in such a way that every rational number is assigned to at least one counting number;If it is assumed that every irrational number can be assigned to at least one counting numbers (like the rationals), then with such a list it is possible to find an irrational number that is not on the list; so is it not possible as there are more irrationals than there are counting numbers, which has shown to be the same size as the rational numbers, thus showing that there are more irrationals than rationals.