Let's denote the two numbers as x and y. From the given conditions, we have the following system of equations:
x + y = 9 xy = 168
By solving the first equation for y (y = 9 - x) and substituting it into the second equation, we get:
x(9 - x) = 168 9x - x^2 = 168 x^2 - 9x + 168 = 0
Factoring the quadratic equation gives us (x - 8)(x - 21) = 0. Therefore, the two numbers are 8 and 21.
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The factor pairs of 168 are (168,1)(84,2)(56,3)(42,4)(28,6)(24,7)(21,8)(14,12)
None of them add up to or differ by 9. (3 and 6) and (2 and 7) are factors of 168.
There are no two real numbers that do. Using complex numbers, these two do: (-3/2 + i√151/2) & (-3/2 - i√151/2) Two numbers that add to -3 and multiply to -40 are -8 & 5 Two numbers that add to 3 and multiply to -40 are 8 & -5 Two complex numbers that add to 3 and multiply to 40 are (3/2 + i√151/2) & (3/2 - i√151/2)
-10 and -3
51
110 and -95
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