-- It depends on how many previous quizzes went into the 65.22%.
-- Also on whether the 65.22% included other things, like homework or attendance.
-- It depends on how much weight the teacher wants to give the Final Exam.
-- In any case, using our vast resources of higher mathematics, we can pretty well guarantee
that your total grade will be lower than 65.22% .
May we wish you the best of luck in the course, particularly if you wind up enjoying it
again next year, and say that we hope for your sake that it's not math.
It is not possible to answer the question without knowing how much of the total each one is worth. If they are both equally important, then the answer is 50% but they are rarely (if ever) equally important. If the test grade is worth x percent of the total - not your grade but how much weight it carries in the total - then the average is [x*70+(1-x)*30]/100
You have to multiply your total points by 0.35
.5985 (final total after discount: 3.3915)
Percentages in sslc reference grade and grade point calculation. First add all of the grades together. Then divide the total by the number of grades that you used in the addition phase. This will give you the average for one class. Now take all classes and add them together. Then divide this number by the number of classes that you previously entered. This will give you the sslc average.
Here is how you do it Do an allegation For 0.01: (.16/.19)X=26g Solve for X=30.875 g is the total gram in the cream for 4% For 0.2: (0.03/.19) (30.875g) = 4.88 g The final answer is 4.88 g of 20% Good luck with Pharmacy MT
Since the final is only worth 25 percent of your grade, you would add your class average of 84 three times. Then take that total of 252 and add it to your exam grade of 75 for a total of 327. Divide this number by 4 to get your final average of 81.75 percent.
If 50 is passing: right now the contribution towards the total grade is (.70)*52, so the total grade = (.70)*52 + (.30)*E [for the final exam grade]. If the target is 50 for the total grade, then 50 = (.70)*52 + (.30)*E, and solve for E = (50 - (.70)*52)/(.30) = 45.3333, so a grade of 46 would put the final grade over 50. By the way, the maximum possible grade of a 100 on the final will result in 66.4 for the total grade.
It's just multiplication. 70 percent of your total will be 85 20 percent of your total will be 75 10 percent of your total will be 96 (85 x 0.70) + (75 x 0.25) + (96 x 0.10) = YOUR GRADE AVERAGE
It is not possible to answer the question without knowing how much of the total each one is worth. If they are both equally important, then the answer is 50% but they are rarely (if ever) equally important. If the test grade is worth x percent of the total - not your grade but how much weight it carries in the total - then the average is [x*70+(1-x)*30]/100
This is the problem of finding a "weighted average", that is to say, some items have more "weight" than others. To avoid confusions, I will convert the 88% to 0.88,and the 12% to 0.12. You can also convert everything to decimals. For example, if you get 80% for your term grades, and 70% for your final exam, you multiply as follows: (80% x 0.88) + (70% x 0.12) = 0.788 or 78.8%. Note that the term grades, having a larger "weight", affect the final grade much more than the exam; the final grade is much closer to the term grades than to the final exam grade. In this example, this works to your advantage, because the final exam has a lower grade.
You have to multiply your total points by 0.35
Final total is 40.50
Final total is 285.00
This "average" is the mode for the class.
You first need to know how much the final contributes to the total grade. Let that be X%, so the final contributes X/100 to the semester grade, and your work, so far, contributes (1 - X/100).If G is your average before the final, and F is the grade earned on the final, and T is the total grade:T = G*(1-X/100) + F*(X/100). Rearranging, we get:F =(T-(1-X/100)*G)/(X/100)So if the final is worth 25%, {X/100 = 0.25}, and you have an 89, now, substituting in, you would need a 93 on the final to get a 90 for the class.If the final is worth 25%, and you have an 95, now, you would need a 75 on the final to get a 90 for the class.
Missing information - you need the worth (weight) for every grade, not just for some of them. The way you calculate this so-called "weighted average" is to multiply each grade by its weight, and add everything up. Then you divide by the total "weight". Example: exam 1: grade is 80; weight is 40. exam 2: grade is 70; weight is 60. 80 x 40 + 70 x 60 = 3200 + 4200 = 7400. Divide this by the total weight (40 + 60 = 100), and you get a weighted average of 74.
35 percent off of 700 is a savings of 245 for a final total of 455.