I'll take this question to mean:
"What is the smallest possible product of two different prime numbers?"
# 0
# 3 # 5 # 6 You've provided two requirements:
# The number must have two factors. # Both factors must be prime. Let's break down the following into possible factors:
0 = 0
3 = 3 * 1
5 = 5 * 1
6 = 1 * 6, 2 * 3
Since neither 0 nor 1 are prime numbers, we're left with only one option.
2 * 3 = 6
It is 27,000.
The two smallest prime numbers are 2 and 3. So, the smallest number that is a product of two different primes that are squared is 22 x 32 = 36.
2×3×5×7=210
The smallest prime factors are 2,3,5,7 thus the smallest number would be the product of these will be 210
9 is the smallest natural number that is odd and composite: 9=3*3. 15 is the smallest natural number that is odd and a product of two numbers different from one and from each other: 15=3*5.
It is 27,000.
30
If the number is a product of two composite numbers, it must be 16, which is the product of 4 and 4. The prime factors of 16 are 2, 2, 2, and 2. The smallest composite number is 4, so the smallest possible product of two composite numbers is 4 x 4 = 16.
When a numbers is multiplied by 13 product consist of all 5's the smallest such numbers is?
1155, 3x5x7x11=1155.
The two smallest prime numbers are 2 and 3. So, the smallest number that is a product of two different primes that are squared is 22 x 32 = 36.
2×3×5×7=210
The two smallest prime numbers are 2 & 3. Their product is thus, 2 x 3 = 6.
Logically, the smallest number with 4 different prime factors would have to be the product of the smallest four prime numbers. So the smallest natural number with four different prime factors is 210 (2*3*5*7).
Forming three three digit numbers that use the numbers 1-9 without repeating, the highest product possible is 611,721,516. This is formed from the numbers 941, 852, and 763.
There are no such numbers. The smallest set of three consecutive composite numbers is {8, 9, 10} and the product of these numbers is 720.
-98