You could make a case for any of them.
You have to find a pattern in the numbers, and exclude the one that messes up the pattern.
If the series is plus one, times two, plus one, times two, etc., the 8 does not belong.
No. One, a counting number, doesn't belong to either of those sets.
It could be any one of them: 3: A 1-digit perfect square - 1 which is not a perfect cube. 7: A perfect cube - 1 8: A 1-digit perfect square - 1 which is also a perfect cube. 15: A perfect 4th power - 1 30: More than 1 away from a perfect power.
Both belong to set of whole numbers. There are infinite prime and composite numbers.
30
8
9 - all the rest are prime
Most probably 48.
The answer is 12 every other numbers are odd numbers, but 12 is an even number
133 ,because all haveroot squares except 133
You have to find a pattern in the numbers, and exclude the one that messes up the pattern.
If the series is plus one, times two, plus one, times two, etc., the 8 does not belong.
1. It is the only one that is neither prime nor composite. It is the only one whose square (cube, higher powers) is the same as itself.
3 ((9-2)(7+1)(8-2)(6+1)(7-2)(5+1))
N, because it is not in the first half of the alphabet.
The answer is KThe letter should be L