It is: 2 times 3^2 times 5 = 90 no indices are needed for 2 and 5
15 = 31*51
648 expressed as a product of its prime factors in index form is 2^3 times 3^4
write the number 14as a product of prime factor?
To express 63 as a product of prime factors in index form, we first need to find the prime factors of 63. 63 can be factored as 3 x 3 x 7. This can be written in index form as 3^2 x 7. Therefore, 63 as a product of prime factors in index form is 3^2 x 7.
It is: 2^1 times 3^2 times 5^2 = 450
As a product of its prime factors: 23*3*5 = 120
48 = 24 x 3
15 = 31*51
648 expressed as a product of its prime factors in index form is 2^3 times 3^4
300
write the number 14as a product of prime factor?
To express 63 as a product of prime factors in index form, we first need to find the prime factors of 63. 63 can be factored as 3 x 3 x 7. This can be written in index form as 3^2 x 7. Therefore, 63 as a product of prime factors in index form is 3^2 x 7.
It is: 2^1 times 3^2 times 5^2 = 450
As a product of its prime factors: 3*7 = 21
72 *23
As a product of its prime factors: 5^3 times 13 = 1625
To express 144 as a product of its prime factors in index form, we first find the prime factors of 144, which are 2 and 3. 144 can be written as 2^4 * 3^2 in index form, where 2 is raised to the power of 4 and 3 is raised to the power of 2. This shows that 144 can be expressed as the product of its prime factors in index form.