tjs
15 = 31*51
648 expressed as a product of its prime factors in index form is 2^3 times 3^4
write the number 14as a product of prime factor?
To express 63 as a product of prime factors in index form, we first need to find the prime factors of 63. 63 can be factored as 3 x 3 x 7. This can be written in index form as 3^2 x 7. Therefore, 63 as a product of prime factors in index form is 3^2 x 7.
72 *23
As a product of its prime factors: 23*3*5 = 120
48 = 24 x 3
15 = 31*51
648 expressed as a product of its prime factors in index form is 2^3 times 3^4
300
As a product of its prime factors: 3*7 = 21
write the number 14as a product of prime factor?
72 *23
To express 63 as a product of prime factors in index form, we first need to find the prime factors of 63. 63 can be factored as 3 x 3 x 7. This can be written in index form as 3^2 x 7. Therefore, 63 as a product of prime factors in index form is 3^2 x 7.
It is: 2^1 times 3^2 times 5^2 = 450
As a product of its prime factors: 5^3 times 13 = 1625
As a product of its prime factors: 3*5*7*7 = 735