Q: Write 98 as a product of its prime numbers?

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98 = 2*7^2.

98 is an even number, thus it is divisible by 2; 98/2 = 49. 49 is simply 72. Since both 2 and 7 are prime numbers, the prime factorization of 98 is 2 X 72.

2 x 7 x 7 = 98

First you need your prime numbers: 2, 3, 5, 7, 11, 13, 17 (and so on)Begin by dividing the smallest prime into the number 98. The smallest prime is '2', so 98 / 2 is 49. 2 will not divide into 49 so find the next highest prime that will divide into 49 evenly. It is '7' so 98 as a product of primes is:2 x 7 x 7, or 2 x 722 x 7 x 7

37 and 61 are two prime numbers having the sum of 98.

Related questions

98 = 2*7^2.

98 = 2 x 7 x 7

98 is an even number, thus it is divisible by 2; 98/2 = 49. 49 is simply 72. Since both 2 and 7 are prime numbers, the prime factorization of 98 is 2 X 72.

As for example 98 as a product of its prime factors is: 2*7*7 = 98

2 x 7 x 7 = 98

25 and 98 are not prime numbers

The prime numbers (factors) of 98 are: 2 and 7

The prime factors of 98 are: 2 7

37 and 61 are two prime numbers having the sum of 98.

First you need your prime numbers: 2, 3, 5, 7, 11, 13, 17 (and so on)Begin by dividing the smallest prime into the number 98. The smallest prime is '2', so 98 / 2 is 49. 2 will not divide into 49 so find the next highest prime that will divide into 49 evenly. It is '7' so 98 as a product of primes is:2 x 7 x 7, or 2 x 722 x 7 x 7

100

As a product of its prime factors: 2*7*7 = 98 or as 2*7^2 = 98