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-9x5 over the square root of x plus 4?

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Anonymous

∙ 15y ago
Updated: 4/28/2022

(-9x^2/√x) + 4

= [-9x^2/x^(1/2)] + 4

= (-9x^2)[x^(-1/2)] + 4

= -9x^[2 + (-1/2)] + 4

= -9x^(2 - 1/2) + 4

= -9x^(3/2) + 4

= -9√x^3 + 4

= -9√[(x^2)(x)] + 4

= -9x√x + 4

Or,

(-9x^2/√x) + 4

= [(-9x^2)(√x)/(√x)(√x)] + 4

= [(-9x^2)(√x)/√x^2] + 4

= [-9(x)(x)(√x)/x] + 4 simplify x

= -9x√x + 4

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∙ 15y ago
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Continue Learning about Calculus

What is 3 square x 5?

3 squared (3^2) equals 9. 9x5 = 45 Therefore the answer is 45.


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How is 9x5 not 45?

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