x = 1, y = 0
3x+5y=48 5y=48-3x-3x+5y=12 -3x+(48-3x)=12-6x=-36x=65y=48-3(6)5y=30y=6(6,6)
Multiply the first equation by 3 to give 9x + 15y = 21
This is Simultaneous equ'ns. 3x + 5y = -1 2x -5y = 16 Add the two eq'ns. This will eliminate 'y' Hence 5x = 15 x = 3 When x = 3 , substitute into either eq'n to yimnd 'y'. Hence 3)3) + 5y = -1 9 + 5y = -1 5y = -10 y = -10/5 = -2 So the solution in ( x,y) form is ( 3, -2).
X intercept is the value of X when Y = 0 -5Y + 3X = 12 ley Y = 0 3x = 12 x = 4
To solve this, present the equation in the standard slope/intercept form of y = mx + c. 'm' is the slope. 2x + 5y = 10 5y = -2x + 10 y = -2/5x + 2 Therefore, -2/5 is the slope.
If: 2x+5y = 2 and -3x-y = -3Then it works out that: x = 1 and y = 0
(4, -1)
(2, 3)
x/5y + 2x/3y = 3x/15y + 10x/15y = 13x/15y
x = 1, y = 0
3x/7 + 5y/14x = 3x*2x/(7*2x) + 5y/14x = (6x2 + 5y)/14x
3x - 8y + 2x - 5 - 5y = 5x -13y - 5
They are: x = -2 and y = -1.
no
x = 4 and y = -1 (4. -1)
3x+5y=48 5y=48-3x-3x+5y=12 -3x+(48-3x)=12-6x=-36x=65y=48-3(6)5y=30y=6(6,6)
8y-3x