maximum value of 6y+10y
4x + 6 = 6x - 12-4x -4x6 = 2x - 12+12 +1218 = 2xx=9
3x - 8 = 7 so x = 5
5x + 3 = 6x + 1 Subtract 5x from both sides: 3 = x + 1 Subtract 1 from both sides: 2 = x
x2 + 6x - 2 = 0 x2 + 6x + 9 = 13 (x + 3)2 = 13 x + 3 = ± √13 x = -3 ± √13
Given 6x-1 = 29: 6x = 30 x = 5 Therefore x² = 25, adding 25 and 5 gives you 30
It is an equation and the value of x is 4
29
x=4 y=1 Therefore, 6x+5y=? Just substitute, and get 6*4+5*1=29
x = 7
The value of x is -3
(9,6)
7x + 9 = 6x + 17 7x - 6x = 17 -9 x = 8
6x+x = 7x
6x plus 3 equals 8x plus 14 when solved mathematically is equal to x = -5.5.
-6x
x=10