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If you have taken physics, you should know the basic kinematic formula

vf²=vi²+2ad

0=vi²-2*16*200

vi=80m/s

Alternatively, if you haven't taken physics yet, you will have to derive an equivalent formula on your own.

We know that the integral of acceleration is equal to velocity so integrate -16 with respect to time to get

v=-16t + vi

for some constant vi.

We also know that the integral of velocity with respect to time is distance so

d=-8t²+vi*t+c

for a constant value c.

Since the distance traveled by the car was 0 at t=0, the value of c is 0.

We also know that there was a constant acceleration so

a=(vf-vi)/t

-16=-vi/t

vi=16t

Combining this with the preceding equation for distance gives us

d=-8t²+vi*t

200=-8t²+16t²

t=5s (reject the negative root)

vi=16t

vi=80m/s

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